HSAB: Hard Soft Acid Base | Ferdinand's Curiousity

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SUMMARY

The discussion centers on the Hard Soft Acid Base (HSAB) theory, specifically analyzing the reaction HI + NaF >>> HF + NaI. Participants identify H as a hard acid and I as a soft base, while Na is a hard acid and F is a hard base. The equilibrium constant (Keq) was calculated using Gibbs free energy values, resulting in Keq = 1.2E-3, indicating that the reaction favors the left side under standard conditions. The conversation also touches on the effects of adding HI to the NaF solution, which can shift the equilibrium to the right.

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  • Understanding of Hard Soft Acid Base (HSAB) theory
  • Basic knowledge of chemical equilibrium and Gibbs free energy
  • Familiarity with calculating equilibrium constants
  • Experience with aqueous chemistry at standard conditions (25°C)
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  • Study the principles of Hard Soft Acid Base (HSAB) theory in depth
  • Learn how to calculate Gibbs free energy changes for chemical reactions
  • Research the effects of concentration changes on chemical equilibrium
  • Explore the concept of borderline acids and bases in HSAB theory
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fairburn96
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Hi guys, my name is ferdinand. I'm curious about HSAB, especially to predict where the reaction goes.
Exp: HI + NaF >>> HF + NaI
H is hard acid
I IS soft base
Na is hard acid
F is hard base, and

HF Is hard.hard
NaI Is hard soft.
The reaction will goes to right or left? And why?
And since hard acid like to bind hard base, why NaI formed?
Thank you...
Terima kasih.And how about the borderline? Is it count as hard or soft?
 
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Have you calculated the equilibrium constant? My quick look says the reaction goes to the left, as you suspect.
 
In water? Or a solid and a gas?
 
Borek said:
In water? Or a solid and a gas?
Good question. I assumed water. OP?
 
insightful said:
I assumed water.

Then it should go to the right, HF is a weak acid.
 
Borek said:
Then it should go to the right, HF is a weak acid.
I used DeltaGf of (all aqueous at 25C):
-129 kcal/gmol for NaF
-71 for NaI
-12 for HI
-66 for HF

and got DeltaGrxn = +4kcal/gmol and using DeltaG = -RTlnKeq, got Keq = 1.2E-3 indicating left side reactants at higher concentrations than right side products.
 
Last edited:
Well, it depends on what your starting material is. Yes, in general the equilibrium is to the left, but if you add HI to the NaF solution, fluoride gets protonated and the shift is to the right.
 

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