Hydraulic Motor & Constant Torque

Click For Summary

Discussion Overview

The discussion revolves around the operation and design of hydraulic motors and pumps, specifically focusing on achieving constant output torque under varying conditions. Participants explore concepts related to hydraulic systems, including the role of hydraulic accumulators, pressure regulation, and the relationship between torque, pressure, and flow rate.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants suggest that constant pressure and fixed RPM can lead to constant output torque, while others challenge this assumption, emphasizing the role of load and flow rate.
  • There is a discussion about the necessity and function of hydraulic accumulators, with some arguing they are not typically needed in simple hydraulic systems, while others propose they could help regulate flow and maintain pressure.
  • One participant raises concerns about ensuring all fluid from the pump goes into the accumulator before reaching the motor, questioning the design of the circuit to prevent bypassing.
  • Several participants mention that maintaining constant torque may not be the primary requirement, suggesting that controlling pressure or speed might be more fundamental.
  • It is noted that for a fixed displacement pump, achieving both constant torque and constant RPM is generally not feasible without specific conditions, such as a fixed load.
  • One participant proposes that using a pressure relief valve could help limit torque, while another suggests that a constant pressure pump is necessary for achieving constant torque at the output shaft.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of hydraulic accumulators and the feasibility of achieving constant torque and RPM simultaneously. There is no consensus on the best approach to design the hydraulic circuit, and the discussion remains unresolved regarding the optimal configuration for the user's specific requirements.

Contextual Notes

Participants highlight limitations in their understanding of how to effectively design the hydraulic circuit, particularly regarding the simultaneous charging and discharging of the accumulator and the implications of varying loads on pressure and torque.

Who May Find This Useful

This discussion may be useful for individuals interested in hydraulic systems design, particularly those exploring the dynamics of hydraulic motors and pumps in applications requiring specific torque and speed control.

HydraulicsLearner
Messages
3
Reaction score
0
Hi, I'm a beginner on hydraulics and have been reading up a lot of literature. But I'm not sure if my assumptions are accurate and I hope I can discuss with other forumers here! My apologies in advance if my questions seem silly!

Background: My goal is to drive a hydraulic motor at constant pressure & constant RPM so that I can achieve constant output torque.

1. Hydraulic pump is a positive displacement pump. (the RPM is variable)

2. I would like the hydraulic motor to produce constant output torque. Is it correct to assume constant pressure & fixed RPM = constant output torque. Would a hydraulic accumulator be able to perform this function - give out constant pressure & fixed output/discharge flow (which would fix the RPM at a specific motor displacement) using a flow controller?

3. How do I design the circuit to make sure all fluid from the pump goes into the accumulator first, before passing into the hydraulic motor? Are there hydraulic accumulators with 2 separate ports (charge & discharge)? Can charge & discharge happen simultaneously at different rates?I'm learning to use Automation Studio to simulate the circuit (please let me know if you can recommend better software for beginners!)

Many thanks!

HydraulicsLearner
 
Engineering news on Phys.org
Output torque from a hydraulic motor is determined by the design details of the motor and the input pressure .

The driven load actually determines what the output torque needs to be and hence what the inlet pressure needs to be .

Running speed is determined by the volume flow of oil going through the motor . Volume flow of oil is set to give running speed suitable for driven load requirements .

Output torque and running speed together determine output power .

You don't normally need a hydraulic accumulator in a simple hydraulic pump / motor drive system .
 
Last edited:
Thanks Nidum!

The reason for thinking of using the accumulator is so that the flow can be regulated (something like a capacitor bank). The accumulator charge rate would be more than the discharge rate to ensure that I have a constant input flow into the motor.

The flow controller will take care of the input flow into the motor. But I don't know how to fix the pressure. Do I need to use a pressurized reservoir to have constant pressure in the circuit? From what I've been reading, it seems that accumulator can be used to maintain system pressure, but I don't understand what that really means.

And I'm trying to figure out how to make sure all the fluid goes into the accumulator first before discharging back into the circuit to drive the motor. It seems like the fluid may bypass the accumulator and go directly to the motor. If that's the case, then it would not function as a flow regulator as I would like it to be. Using the analogy of a hydro dam where water gets collected and then discharged at a slower rate via a smaller outlet, I'm trying to emulate a hydro dam with an accumulator.

If possible, I'm hoping it can be simultaneously charged & discharged so that the circuit is constantly flowing.

I look forward to more discussions!
 
Something is out of place here for me.

Most of the hydraulic systems I work with on injection moulding machines have variable displacement pumps. Displacement is adjusted according to feedback from a control system. Usually comprising of a transducer and a control circuit.

Feedback is usually in the form of pressure or speed. The control works out the displacement required to achieve the required pressure or speed. Such systems are well understood and have been used for many years.

Maintaining a constant torque might be required (to maintain a constant pressure for example) but torque is normally only secondary to the control input.

My feeling on your post is that torque is not your primary input or requirement. Something more basic (and therefore easier to measure) like speed or pressure is what you need I think. Simplifying your problem (or explaining it fully for more precise help) may solve your problem

I may be wrong. If torque is your primary requirement then finding a way to transduce the torque on the output of your system to a voltage and feeding that back through the control to your pump will give you closed loop control.

Accumulators are only typically used to provide large volumes at a given pressure for quick movements. As long as your torque requirements do not exceed the flow and pressure capacity of the pump you will not need one.
 
  • Like
Likes   Reactions: OCR
For a fixed displacement pump you will get constant torque by running at a constant pressure. You will get a constant RPM by running at a fixed flow rate. You cannot have it both ways, always.

The way to achieve both, most of the time, would be to run an electric motor driving a pump that sets the flow rate. A fixed displacement pump will then be driven at a fixed speed. By placing a pressure relief valve across the circuit you will limit the torque to a maximum.

Any attempt to draw more power from the hydraulic motor output than power = ( RPM * torque ), will see a drop in either RPM or torque from the specified settings.
 
I don't think it is typical at all to use an accumulator in a hydraulic motor circuit. Hydrostatic drive systems consist of a variable displacement pump and a hydraulic motor that is sometimes a variable displacement unit. Skid steer loaders that have 2 speeds will sometimes switch to a smaller displacement by changing the position of the swash plate in the motors. But that is pretty much it, at least in terms of main components.
-
In your case, you can't have constant pressure and constant speed unless the load is fixed. If you want a fixed speed out of the motor you need a constant specific flow. If the load changes, the pressure will change. You cannot really have it any other way and I don't know why you would need to in a hydraulic motor circuit. Think of it this way: Replace the hydraulic motor with an imaginary orifice in which you can vary the size. Small orifice represents large mechanical load on the motor. Large orifice represents a small mechanical load on the hydraulic motor. Hook this to a positive displacement pump turning at a specific RPM. What do you think will happen?
 
Thanks guys for all the replies! I'm digesting all the information and explanation, they are definitely very helpful!
 
Baluncore said:
For a fixed displacement pump you will get constant torque by running at a constant pressure. You will get a constant RPM by running at a fixed flow rate. You cannot have it both ways, always.

The way to achieve both, most of the time, would be to run an electric motor driving a pump that sets the flow rate. A fixed displacement pump will then be driven at a fixed speed. By placing a pressure relief valve across the circuit you will limit the torque to a maximum.

Any attempt to draw more power from the hydraulic motor output than power = ( RPM * torque ), will see a drop in either RPM or torque from the specified settings.

I am designing a machine that has variable RPM and I have to couple a hydraulic motor on the same shaft (there is no other way) I need constant torque at the output side( variable rpm) is this possible?
 
  • #10
Welcome to PF.
You can have constant torque at the output shaft if the output shaft is driven by only one hydraulic motor. The pump that supplies that motor would need to be a constant pressure pump. I would need to see a diagram of your machine to be sure.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
12
Views
5K
  • · Replies 19 ·
Replies
19
Views
4K
Replies
24
Views
3K
Replies
58
Views
8K
  • · Replies 18 ·
Replies
18
Views
751
  • · Replies 4 ·
Replies
4
Views
4K
Replies
6
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K