- #1
Master J
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The Hydrogen Atom wave function.
With the substitution u(r) = r.R(r)
p=kr
We get a simplified version: d^2u/dp^2 = [1 - (p_0)/p + l(l + 1)/(p^2) ].u
Im sure some of you have seen that before.
Now, in the limit, p goes to infinity, I understand that we get u = A.exp[-p], but in the limit that p goes to 0, the answer is:
d^2u/dp^2 = [l(l + 1)/(p^2)].u
I don't get where that comes from. Surely the terms with p at the bottom explode and become infinite??
With the substitution u(r) = r.R(r)
p=kr
We get a simplified version: d^2u/dp^2 = [1 - (p_0)/p + l(l + 1)/(p^2) ].u
Im sure some of you have seen that before.
Now, in the limit, p goes to infinity, I understand that we get u = A.exp[-p], but in the limit that p goes to 0, the answer is:
d^2u/dp^2 = [l(l + 1)/(p^2)].u
I don't get where that comes from. Surely the terms with p at the bottom explode and become infinite??
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