Hydrogen -Energy State Transitions

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SUMMARY

The discussion focuses on deriving the algebraic relationship between the wavelengths of transitions in hydrogen-like ions with atomic number Z and hydrogen itself. The key equation used is hν(n1, n2) = C1Z^2(1/n2^2 - 1/n1^2), which relates energy transitions to wavelength through ν = c/λ. The conclusion establishes that the wavelength for hydrogen-like ions can be expressed as λ = 1/Z^2 * (λ for H), highlighting the direct influence of atomic number on the wavelength of emitted or absorbed light during transitions.

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  • Understanding of quantum mechanics principles, specifically energy state transitions.
  • Familiarity with the Rydberg formula for hydrogen-like atoms.
  • Knowledge of the Planck constant and its role in energy calculations.
  • Basic algebraic manipulation skills to rearrange equations.
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  • Learn about the implications of atomic number on spectral lines.
  • Explore the concept of energy quantization in quantum mechanics.
  • Investigate the differences in spectral emissions between hydrogen and hydrogen-like ions.
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Homework Statement



Find the (algebraic) relationship between the wavelengths of the equivalent transitions (i.e. same n1 and n2) for hydrogen-like ions of atomic number Z and hydrogen itself.

Homework Equations



I know:

[tex]h\nu (n_{1} , n_{2} ) = C_{1}Z_{1}^2(\frac{1}{n_{2}^2} - \frac{1}{n_{1}^2})[/tex]

And

[tex]\nu = \frac{c}{\lambda}[/tex]



The Attempt at a Solution



But that's as far as I can get really. I know putting Z as 1 will give me the simplest case for Hydrogen, but I'm still a bit perplexed at what the question actually wants. I could rearrange for [tex]\lambda[/tex], but I'm still unsure if that's on the right lines?

Thanks.
 
Last edited:
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Use lambda = h/v = h^2/(hv) = h^2/(C*Z^2*X)
where X is the big pair of brackets with the transition numbers in it.
You want to compare this with the same expression for hydrogen which is h^2/(C*1*X) unless the C is different for hydrogen, too.
They are the same except for the Z^2 so you'll end up with
lambda = 1/Z^2 * (lambda for H)
 
Sorry, I just realized I've written rubbish:

[tex]\nu = \frac{c}{\lambda}[/tex] Is what is meant to be there!

Sorry
 

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