Hydrostatics, Length of a mercury column

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The problem involves calculating the length of a mercury column in a barometer tube inclined at 60° when atmospheric pressure is 75 cm of mercury. Using Pascal's Law, the formula l = h / sinϑ is applied, leading to an initial calculation of approximately 87.2 cm. However, the textbook states the correct answer is 86.6 cm, suggesting the need for more significant figures in intermediate calculations. It emphasizes the importance of rounding results only at the final step to achieve accuracy. Proper calculation methods are crucial for precise results in hydrostatics.
Ishraq Begum
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Homework Statement


What will be the length of mercury column in a barometer tube, when the atmospheric pressure is 75 cm of mercury and the tube is inclined at an angle of 60° with the horizontal direction?

Homework Equations


Pascal's Law

The Attempt at a Solution


l ⋅ sinϑ = h
l = h / sinϑ
l = h / sin 60
l = 75 / 0.86
l = 87.2
but the correct answer given in the textbook is 86.6
 
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Use more significant figures for intermediate calculations. Only round results at the end.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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