I am confuse in finding Argumnet of Complex Number

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The discussion revolves around understanding the argument of complex numbers in different quadrants. For complex numbers like (2+2i) in the first quadrant, the angle is 45 degrees, while for (-2+2i) in the second quadrant, the angle is adjusted to 135 degrees by adding 180 degrees to the reference angle. In the third quadrant, such as with (-2-2i), the angle is calculated as 225 degrees, again adjusting the reference angle accordingly. The fourth quadrant example (2-2i) yields an angle of -45 degrees, which can be expressed positively as 315 degrees. The conversation emphasizes the need to adjust angles based on the quadrant to determine the correct argument for complex numbers and their logarithmic and polar forms.
urduworld
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hi PF

1. (2+2i) First Quadrant
2. (-2+2i) Second Quadrant
3. (-2-2i) Third Quadrant
4. (2-2i) Fourth Quadrant

consider (2+1i) then Tan^-1(2/2) which will be 45 degree
if we consider (-2+2i) then it will be -45 degree but angle will not -45 degree actually we get answer by adding or deducting 180 or some like this i want to know what we have to add or subtract i am confuse about this

also what to do for third and fourth quadrants

i want to know this for Log of complex number and Polar form
Please help me
Thanks in advance :)
 
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urduworld said:
hi PF

1. (2+2i) First Quadrant
2. (-2+2i) Second Quadrant
3. (-2-2i) Third Quadrant
4. (2-2i) Fourth Quadrant

consider (2+1i) then Tan^-1(2/2) which will be 45 degree
if we consider (-2+2i) then it will be -45 degree but angle will not -45 degree actually we get answer by adding or deducting 180 or some like this i want to know what we have to add or subtract i am confuse about this
You seem to be confused between the reference angle and the angle as measured from the positive real axis. For 2 + 2i, the reference angle and the angle itself are both 45 degrees, or pi/4. For -2 + 2i, the reference angle is also 45 degrees (not -45 degrees), but since the angle is in the second quadrant, the actual angle is 180 - 45 = 135 degrees, or 3pi/4. If you calculate the angle using the inverse tangent function, you have t-1(-2/2) = -45 degrees. You have to add 180 degrees to this, because your angle is in the 2nd quadrant, so you get 180 + (-45) = 135 degrees again.

The range of the inverse tangent function is (-90, 90) (in degrees), or (-pi/2, pi/2), so if your angle is not in the 1st or 4th quadrants you have to adjust the value to get the angle you need.

If your angle is in the third quadrant, as it is for -2 - 2i, you'll have tan-1(-2/(-2)) = 45 degrees. The actual angle is 180 + 45 = 225 degrees, or 5pi/4.
urduworld said:
also what to do for third and fourth quadrants

i want to know this for Log of complex number and Polar form
Please help me
Thanks in advance :)
 
Last edited:
this means i have to add 180 in all the condition except if it is in first
 
I didn't talk about a fourth quadrant angle, but maybe you can figure out what you need to do. If z = 2 - 2i, the argument would be -45 degrees. As a positive angle, what would it be?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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