I am confused by the concept of space-time in special relativity

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Space-time in special relativity combines three spatial dimensions with one time dimension, creating a unified framework known as Minkowski spacetime. In contrast, Newtonian physics operates with Galilean spacetime, where space and time are treated as separate entities, leading to less frequent references to the term "spacetime." The intertwining of space and time in special relativity reflects the effects of relative motion on measurements of time and distance. This distinction clarifies why "spacetime" is more commonly associated with Einstein's theories rather than Newton's. Understanding these differences is essential for grasping the implications of relativity.
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I am confused by the concept of space-time in special relativity, I have 3 spatial dimensions and 1 time dimensions. In Newtonian physics don't I also have 3 spatial dimensions and 1 time dimension? Then why call it space time in special relativity and not in Newtonian physics?
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I am confused by the concept of space-time in special relativity, I have 3 spatial dimensions and 1 time dimensions. In Newtonian physics don't I also have 3 spatial dimensions and 1 time dimension? Then why call it space time in special relativity and not in Newtonian physics?
 
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It is called spacetime in Newtonian physics too.

The difference is that Newtonian physics has Galilean spacetime where space and time are much less intertwined than in the Minkowski spacetime of special relativity or the general Lorentzian manifolds of general relativity. It istherefore much less common to talk about spacetime in Newtonian physics.
 
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Thread 'Chain falling out of a horizontal tube onto a table'

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
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