I am definitely missing something in this relation

[nistaria]

Homework Statement

For each of the following relations on the set of all real numbers, say whether it is reflexive, symmetricm anti-symmetric, and transitive.

Homework Equations

c)x=1

The Attempt at a Solution

According to class notes I took, as this simple question was solved in class
Reflexive: no (2,2) is not in the relation
Symmetric: no if(1,2)\inR(relation,not real number) but (2,1)\notinR
Anti-symmetric: yes
let (x,y)\inR
===>x=1
if y\neqx, then y\neq1 and (y,x)\notinR since y\neqx=1

Transitive?
Yes
let (x,y)\inR and (y,z)\inR
===> x=1 and y=1
===> (x,z)\inR

My question is .. how is it possible that it is not reflexive transitive, symmetric or for that matter is anti-symmetric?
How is it possible that y does exists in the relation? Wouldn't that be a false value to begin with? As in if we have a false value then we cannot compare it to the existing relation?

 

[nistaria]

Alright well I just figured it out.. i really need to stop pulling these all nighters and my only source of nutrition being candy bars and coffee.
The answer is so obvious and I definitely didn't see it.