I cant understand the exact meaning of

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The discussion clarifies the concepts of limit inferior (lim inf) and limit superior (lim sup) in the context of sequences. Lim inf is defined as the infimum of all subsequential limits, while lim sup is the supremum of all subsequential limits. The confusion arises from the misunderstanding that lim inf must be less than or equal to the limit point of a converging subsequence. The example provided illustrates that for the sequence (-1)^n/n, both lim inf and lim sup equal 0, while for the sequence (-1)^n(n+1)/n, lim inf equals -1 and lim sup equals 1, demonstrating the behavior of subsequences.

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transgalactic
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http://img212.imageshack.us/img212/3649/84677187li3.gif

i thought that lim inf is the smallest inf ever so
why in this drawing its located on the right of inf(Xn)
and they say that lim inf >= of point d
how could i t be
the subsequence converges to d .lim inf cannot be larger then D (it is D)

and the same thing goes for the lim sup
??
 
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transgalactic said:
http://img212.imageshack.us/img212/3649/84677187li3.gif

i thought that lim inf is the smallest inf ever
If have no idea what "smallest inf ever" could mean! I suspect you have a completely wrong idea of what lim inf and lim sup are.

"lim inf" of a sequence is the inf of all subsequential limits.
"lim sup" of a seque nce is the sup of all subsequential limits

so
why in this drawing its located on the right of inf(Xn)
and they say that lim inf >= of point d
how could i t be
the subsequence converges to d .lim inf cannot be larger then D (it is D)

and the same thing goes for the lim sup
??
Since I can't see the drawing you are talking about, I have no idea.
If a sequence converges to anything, the all subsequences converge to the same thing so both lim inf and lim sup must be equal to that.

For example, the sequence (-1)n/n converges to 0 so both lim sup and lim inf are 0. That has nothing to do with the fact that there are members of the sequence both above and below 0.

If the sequence were an= (-1)n (n+1)/n, then there are two convergent subsequences: an with n even is (n+1)/n which converges to 1 and with n odd is -(n+1)/n which converges to -1. lim inf= -1 and lim sup= 1. However, all an with n even are greater than 1 and decrease to 1, while all an with n odd are less than -1 and increase to -1.
 
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thanks i think i am getting the idea
 

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