I can't understand this linear equation at all

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SUMMARY

The discussion centers on graphing the linear equation 3x - 6y = 0 and finding its intercepts. Participants clarify that the equation is already in standard form and explain how to derive additional points for graphing. The key method involves substituting values for x to find corresponding y values, with (0, 0) being one intercept. The correct approach to solving for y when x = -2 is emphasized, correcting previous misunderstandings.

PREREQUISITES
  • Understanding of linear equations and their forms (standard and slope-intercept).
  • Ability to solve for variables in algebraic equations.
  • Familiarity with graphing techniques for linear equations.
  • Basic knowledge of intercepts and slopes in coordinate geometry.
NEXT STEPS
  • Learn how to convert linear equations from standard form to slope-intercept form.
  • Practice graphing linear equations using various points to confirm accuracy.
  • Explore the concept of intercepts and their significance in graphing.
  • Study the relationship between the slope and the angle of a line on a graph.
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Students studying algebra, educators teaching linear equations, and anyone seeking to improve their graphing skills in mathematics.

xilc
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Homework Statement


Alright...

3x - 6y = 0, Graph the linear equation, finding it's intercepts.




Homework Equations


I've tried solving it by putting 0 in for x / y, and I've also tried putting -2 in for x / y, so that y = 2 when I move it over, and the system for my college homework tells me it's wrong either way. I simply don't get it.


The Attempt at a Solution


Quite obviously, if I try to solve it, I get 0,0. However, I have no idea how to get any other problem solution at all... If I put 0 in for x or y to simply get one variable, it ends up being y = 0, or x = 0... But it's telling me I have to graph multiple points. How would I do this?
 
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you have the equation of a line going thru the origin 0,0 so now can you see what the slope of the line is?

Also can you see other points that might be on the line say pick x=2 then what is y?...
 
It might help to put the original equation for the line into standard form,

y = ax + b

From this, you are able to determine the slope, a,and the y-intercept, b

You can also generate points and plot the line.
 
SteamKing said:
It might help to put the original equation for the line into standard form,

y = ax + b

From this, you are able to determine the slope, a,and the y-intercept, b

You can also generate points and plot the line.

It's already in standard form, what are you talking about?

y = mx + b is slope intercept...

Ax + By = C is standard form, and it's in standard form already...
 
xilc said:
It's already in standard form, what are you talking about?

y = mx + b is slope intercept...

Ax + By = C is standard form, and it's in standard form already...

Just convert your equation to intercept form. Using that you can graph by just knowing two points. Intercept form is x/a + y/b=1
 
xilc said:

Homework Statement


Alright...

3x - 6y = 0, Graph the linear equation, finding it's intercepts.




Homework Equations


I've tried solving it by putting 0 in for x / y,
So the line goes through the point (0, 0) (and give both x and y intercepts)

and I've also tried putting -2 in for x / y, so that y = 2
When you put -2 for x, you get -6- 6y= 0

when I move it over,
You get 6y= -6. That does NOT give y= 2. Try again.

and the system for my college homework tells me it's wrong either way. I simply don't get it.


The Attempt at a Solution


Quite obviously, if I try to solve it, I get 0,0. However, I have no idea how to get any other problem solution at all... If I put 0 in for x or y to simply get one variable, it ends up being y = 0, or x = 0... But it's telling me I have to graph multiple points. How would I do this?
Well, yes, a line is determined by two points. One of those points is (0, 0). To get another point put in any value of x you like. x= -2 works fine but you have to solve the equation for y correctly!
 

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