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I dont know if I did the problem right check please.

  • Thread starter yaho8888
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  • #1
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[SOLVED] I dont know if I did the problem right check please.

Homework Statement


A jet is diving vertically downward at 1200km/hr
the pilot can withstand a maximum acceleration of 4G, before losing consciousness, at what height must the plane start a quarter turn to pull out of the dive? Assume the speed constant.


Homework Equations



A=V^2/r

The Attempt at a Solution



for this circular motion we know that h = radius of the circle
so
4G=(1200km/hr)^2/h
4G=4*9.8m/s=39.2m/s=508032km/hr^2(Not sure if convert it right)
508032=1200^2/h
h=2.834Km
Is this right, the answer has to be in Km so I convert the 4G.
 

Answers and Replies

  • #2
Shooting Star
Homework Helper
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If you want the ans in km/hr, convert everything to those units.

4g = v^2/h =>
4*(9.8/1000)/(1/3600)^2 = 1200^2/h. The value of h will be in kms.

EDIT: 1/3600 corrected (1/3600)^2, after being pointed out by yaho8888.
 
Last edited:
  • #3
PhanthomJay
Science Advisor
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Looks good; you incorrectly typed m/s instead of m/s^2 in your 4G calculation, but the math came out OK.
 
  • #4
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If you want the ans in km/hr, convert everything to those units.

4g = v^2/h =>
4*(9.8/1000)/(1/3600) = 1200^2/h. The value of h will be in kms.
wouldn't that be 4*(9.8/1000)/(1/3600)^2
 
  • #5
Shooting Star
Homework Helper
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wouldn't that be 4*(9.8/1000)/(1/3600)^2
Yes. Thanks for pointing out the typo. I'll edit the post.
 

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