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yaho8888
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[SOLVED] I don't know if I did the problem right check please.
A jet is diving vertically downward at 1200km/hr
the pilot can withstand a maximum acceleration of 4G, before losing consciousness, at what height must the plane start a quarter turn to pull out of the dive? Assume the speed constant.
A=V^2/r
for this circular motion we know that h = radius of the circle
so
4G=(1200km/hr)^2/h
4G=4*9.8m/s=39.2m/s=508032km/hr^2(Not sure if convert it right)
508032=1200^2/h
h=2.834Km
Is this right, the answer has to be in Km so I convert the 4G.
Homework Statement
A jet is diving vertically downward at 1200km/hr
the pilot can withstand a maximum acceleration of 4G, before losing consciousness, at what height must the plane start a quarter turn to pull out of the dive? Assume the speed constant.
Homework Equations
A=V^2/r
The Attempt at a Solution
for this circular motion we know that h = radius of the circle
so
4G=(1200km/hr)^2/h
4G=4*9.8m/s=39.2m/s=508032km/hr^2(Not sure if convert it right)
508032=1200^2/h
h=2.834Km
Is this right, the answer has to be in Km so I convert the 4G.