I don't know where went wrong help needed

  • Thread starter lmlgrey
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In summary, a small pellet with a mass of 5.70 mg and a charge of 7.75*10^-7C is accelerated from rest at a potential difference of 4.50E+3 V between two parallel conducting plates in deep space. The work done on the charge is equal to the kinetic energy of the pellet, which can be calculated by multiplying the potential difference and the charge. After solving for the kinetic energy and converting the mass to kilograms, the speed of the pellet is found to be 1.106 m/s. However, this answer may be incorrect due to a discrepancy in using the appropriate SI units.
  • #1
lmlgrey
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1. Two parallel conducting plates that are in deep space are brought to a potential difference of 4.50E+3 V, and a small pellet of mass 5.70 mg carrying a charge of 7.75*10^-7C accelerates from rest from the positive plate. With what speed will it reach the other plate?








It seemed pretty obvious for me that by multiplying the potential difference and the charge on the pellet, the work done on the charge will be calculated. This work is equivalent to the kinetic energy of the pellet,
So change in U = 4.5*10^3 V * 7.75*10^-7 C = 3.4875*10^-3 J
and change in U = Kinetic energy = 0.5*(0.0057g)*v^2
solving for V I got v= 1.106 m/s
but the answer is wrong... can someone give me a hint?
 
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  • #2
Kilogram is the SI standard mass unit to use with Joules. Convert the mass accordingly.
 
  • #3


It's great that you were able to identify the relationship between potential difference and kinetic energy. However, there may be a mistake in your calculation as the units for mass should be in kilograms, not grams. This could be the reason for the discrepancy in your answer. Also, make sure to double check your conversions between units to ensure accuracy. Another thing to consider is the direction of the electric field between the plates and how it may affect the acceleration of the pellet. Keep exploring and double checking your calculations, and don't be afraid to seek help from your peers or a mentor if needed. Good luck!
 

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