I dont understand some part of work energy theorem

Click For Summary

Homework Help Overview

The discussion revolves around the work-energy theorem, specifically in the context of an elevator being pulled by a force equal to its weight while moving at a constant velocity. Participants are exploring the implications of net force and energy changes in this scenario.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are examining the relationship between work done, potential energy changes, and the concept of power in the context of the elevator's motion. Questions arise regarding the treatment of forces and the implications of constant velocity on work and power.

Discussion Status

Some participants have provided insights into the roles of conservative and non-conservative forces in the work-energy theorem. There is an ongoing exploration of how to correctly account for work and power in the context of the elevator's movement, with no explicit consensus reached.

Contextual Notes

Participants are navigating assumptions about net force and the definitions of work and power in relation to the elevator's constant velocity. The discussion reflects a need for clarity on these concepts without resolving the underlying questions.

madah12
Messages
326
Reaction score
1

Homework Statement



[tex]\Sigma[/tex]W = [tex]\Delta[/tex]E
so if we have an elevator getting pulled by force equal to it's weight making it move with a constant velocity then the net force is equal to 0 so the sigma W is equal to zero but isn't there non zero change in potential energy ?

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
If E is the total mechanical energy, you only need to account for the work done by the non-conservative forces. In this case, you have two forces on the elevator: the force of gravity, which is a conservative force, and the tension in the cable, which is non-conservative. The only work that you include on the lefthand side is the work done by the tension. The work done by gravity is already accounted for via the gravitational potential energy.
 
oh I see, would that said elevator have any power? because P=F*V=0*V=0
so then would it have 0 power but then it will have zero work or should we not take the net force?
 
It depends what exactly the question is. If you're asking "What power is required to lift the elevator at a speed V?" you'd only consider the force doing the lifting, that is, the tension, and multiply it by the speed to find the power needed.
 

Similar threads

Replies
3
Views
2K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
3K
Replies
11
Views
3K
  • · Replies 58 ·
2
Replies
58
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K