I have a few questions, this one is special relativity.

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Homework Help Overview

The discussion revolves around a special relativity problem involving the twin paradox, where one twin travels at a significant fraction of the speed of light while the other remains on Earth. The original poster is attempting to compare the biological ages of the twins after a specified time has elapsed on Earth.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the time dilation formula but expresses confusion regarding the use of velocity as a fraction of the speed of light (v/c) and whether to square this value. They also question how to interpret the results of their calculations in terms of the astronaut's age.

Discussion Status

Participants are providing guidance on the correct application of the time dilation formula and discussing the implications of the calculations. There is an ongoing exploration of how to correctly interpret the results, with some participants reiterating the importance of the gamma factor in determining the astronaut's age relative to the Earth twin.

Contextual Notes

There is mention of the original poster's struggle with the notation and calculations, including a lack of familiarity with LaTeX formatting. The discussion includes a reminder that participants should show their work and articulate their reasoning to facilitate assistance.

chevycamaro1987
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1. On his 25th birthday, the astronaut twin leaves on a long space journey at an average speed of v/c= 0.98. He returns after 20 earth-years have elapsed, to celebrate his earth-twin's 45th birthday. Compare their biological ages.



2. 1/ square root 1- v^2/c^2, My teacher is using v/c instead of giving me a velocity which is throwing me off, I'm not sure if I square the .98 or not.



3. 1/ square root 1- v^2/c^2, so what I was doing was putting the .98 and squaring it, which gives me .9604. I subtracted the 1 from .9604, and got .0396. I inverse the .0396 and get an answer of 25.25...Do I add that 25.25 to the original age of the astronaut which would give me an answer of 50.25 or is the astronauts age just 25.25...?
 
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Welcome to PF. We will not do your homework for you. Please show us your work, and discuss why you are unable to proceed. We will help by pointing you in the correction direction.

- Warren
 
i edited it chroot, is that better?
 
sorry i don't know how to use latex!
 
You're making this way too hard, I think.

Find gamma for v=0.98c. That's 1/Sqrt[1 - (0.98)^2].

The number of years elapsed onboard the spaceship is shorter than the time elapsed on Earth by a factor of gamma. So, the number of years elapsed on board the spaceship is 20/gamma.

- Warren
 
chroot said:
You're making this way too hard, I think.

Find gamma for v=0.98c. That's 1/Sqrt[1 - (0.98)^2].

The number of years elapsed onboard the spaceship is shorter than the time elapsed on Earth by a factor of gamma. So, the number of years elapsed on board the spaceship is 20/gamma.

- Warren

So i tried the formula you gave me (i was using the same one i thought but i got 50, i don't know what happen) and got an answer of 5.03. i don't understand your last part, the 20/gamma. since the 20 years elapsed, I'm dividing it by gamma= 5.03 and then do i add that to the astronauts original age giving him 30 years compared to his twin's 45th? this is just way too much for my understanding. sorry if I am being a pain
 
In the twenty years on earth, one twin's age increased by 20. Since he was 25 to begin with, he's 45 at the end of that time period.

In the same twenty of years on earth, the twin is flying around, and has aged only 5.03 years. The twin was also 25 when the experiment started, so now he's approximately 30 years old.

- Warren
 

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