I know f=ma but I need velocity

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The discussion centers on calculating the second force acting on a particle moving at a constant velocity of v = (3 m/s)I - (4 m/s)j, given that one of the forces is F1 = (2 N)I + (-6 N)j. According to Newton's first law, the net force acting on an object moving at constant velocity must be zero, indicating that the sum of all forces equals zero. Therefore, the second force F2 must be equal to -F1, which results in F2 = (-2 N)I + (6 N)j, ensuring that the particle maintains its constant velocity.

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While two forces act on it a particle is to move at the constant velocity v= (3m/s)I - (4m/s)j. One of the forces is F1=(2n)I +(-6n)j what is the other force?


I want to say (1n)I + (2n)j but then I couldn't decided why that would be true. I guess I liked those numbers because if the mass were 1kg it would make the acceleration fit the requirements, I don't think I'm thinking about it correctly.
 
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Have a think about how Newtons first law would be applied to this situation.
 

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