I lack the competence in basic physics

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Homework Help Overview

The problem involves a bike and rider with a total mass of 86 kg coasting at a velocity of 9 m/s while experiencing a 40 N headwind for 12 seconds. The discussion centers on calculating the final velocity of the rider after accounting for the effects of the headwind.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between force, impulse, and momentum, questioning the calculations related to the change in velocity. There is discussion about the correct interpretation of the impulse and its effect on the rider's momentum.

Discussion Status

Some participants confirm the calculations presented, while others express confusion over specific numerical results. There is a recognition of the correct approach to the problem, but discrepancies in the final numerical values lead to further clarification and correction among participants.

Contextual Notes

Participants note the importance of significant figures in the context of the problem, and there is acknowledgment of potential calculation errors that may have influenced the discussion.

CaptainUno
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Homework Statement



A bike and its rider have a total mass of 86kg. If the rider is coasting on level ground at 9m/s and a 40N head wind acts on the rider for 12 seconds. What is the final velocity of the rider?

Homework Equations





The Attempt at a Solution


Assumption (Converting the Air resistance to velocity) : 40N x 12s = 480
480/86kg= 5.58m/s
9m/s - 5.58m/s = 3.42m/s is this correct or am I using the wrong equations
 
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Looks correct to me.

$$\int_0^{12} 40 dt= 40*12=480$$ so we have
Next because the above is impulse, and impulse is equal to $$\Delta{p}$$ which is $$mv$$. Rearranging the equation $$480=m \Delta{v}$$

$$\frac{480}{mass} = \Delta{v}$$ where $$\Delta{v} = v_f-v_i$$

For your problem, we have
$$\Delta{v} = 9-\frac{480}{86} \approx 3.4$$

The paragraph below is incorrect.

[strike]Now we have the change in velocity. Subtract 5.6 from 9, which you did, and you should have the correct answer. [/strike]

NOtE: your problem has only 1 significant figure. So technically $$v_f \approx 3$$
 
Last edited:
(I'm assuming you know Momentum = mass*velocity)Have you ever heard the following definition of force? "Force is change in momentum per (change in) time"
(in math: F=\frac{ΔP}{Δt}=m\frac{Δv}{Δt}=ma)

This means if you multiply the force by the time you will get the change in momentum
(40\cdot 12=480)

Subtract that (because it's in the opposite direction) from the original momentum and you will have final momentum of the bike rider
(And then divide by the mass to get the final speed)

\frac{9\cdot 86-480}{86}=9-\frac{480}{86}=3.42

Your answer was correct but it's good to understand why what you did works.
 
Last edited:
[strike]I believe 9-(480)/86 isn't 3.4. It's 5.6.[/strike]

But I like your explanation better than mine :)

Edit : nvm your math is correct
 
Shinaolord said:
I believe 9-(480)/86 isn't 3.4. It's 5.6.

So you're saying 480/86 is about 3.4? My calculator disagrees :smile:
 
Nathanael said:
So you're saying 480/86 is about 3.4?
Edited; I was wrong. I had done something wron in my first post. Apologies
I messed up with My calculator. somehow :0
 

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