Basic Question about Relativity Reference Frame Shifts

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SUMMARY

The discussion centers on the concept of reference frame shifts in relativity as presented in Shankar's Introductory Physics course. Observer S is stationary, while Observer S' moves with velocity u, leading to a shift in the x origin of S' relative to S. The participants clarify that while both observers agree on the time origin at t=0, the x origin of S' is displaced to the right due to its motion. The misunderstanding regarding the nature of this shift versus a stretch is resolved, emphasizing the importance of understanding relative motion in special relativity.

PREREQUISITES
  • Understanding of basic concepts in special relativity
  • Familiarity with reference frames and relative motion
  • Knowledge of Shankar's Introductory Physics course content
  • Basic grasp of time dilation and length contraction principles
NEXT STEPS
  • Study the Lorentz transformation equations in detail
  • Explore the implications of simultaneity in different reference frames
  • Investigate the concept of time dilation and its mathematical derivation
  • Review examples of relative motion in various physical scenarios
USEFUL FOR

Students of physics, educators teaching special relativity, and anyone seeking to deepen their understanding of reference frame shifts and their implications in relativistic contexts.

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Homework Statement


I'm using Shankar's Introductory Physics course and I can't get a question out of my head regarding his setup of Relativity.

There are two observers, S and S'. Observer S is stationary, while Observer S' is sliding past S (to the right) with velocity u. They agree to set their origin of t=0 at the moment when Observer S' passes Observer S. Shankar states that while the two observers will agree on their time origin, the x origin of Observer S' will be shifted to the right relative to the x origin of Observer S, by virtue of the fact that Observer S' is moving.

My question is a very simple conceptual question. Why does the x origin of Observer S' experience a point shift due to its velocity? Wouldn't it make more sense for Observer S' to experience something more like a stretch, in which Observers S and S' agree on the starting point of the x origin (the x origin of S), but due to the velocity of S', the x origin of S' covers a stretch of distance in that span of time versus just a point?

For example, if I were on a train and someone were on the ground, and we agreed to press a stopwatch the moment we passed each other, intuitively I can't figure out why that would simply mean that I pressed my stopwatch at a distance 3 feet (just as an example) from where he pressed his stopwatch.

Homework Equations

The Attempt at a Solution

 
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The x origin of observer S' is moving relative to the x origin of observer S. While they align at time t=0, the x-origin of observer S' moves further and further to the right as time passes.
 
phyzguy said:
The x origin of observer S' is moving relative to the x origin of observer S. While they align at time t=0, the x-origin of observer S' moves further and further to the right as time passes.
Now I get it. I misunderstood how he presented the problem. Thank you!
 

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