I need a spherically symmetric spin-dependent NN potential

In summary, the conversation discusses the writer's struggles with their BSc thesis, which aims to predict the bound states of two-nucleon systems using a simple QM two body problem. The writer initially plans to use the one-pion exchange potential (OPEP) but later realizes it has a tensor component, leading them to consider using the simple Yukawa potential instead. However, this potential does not differentiate between nucleons and would not demonstrate the exclusion principle and spin-dependence of the nuclear force, which is the main focus of the thesis. The conversation also touches on the writer's attempts to understand spin, isospin, and the workings of OPEP, including their confusion about setting the tensor part to zero. The writer
  • #1
Phi6er
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First, I'll give a little background so you guys know why I've arrived at this issue. I'm writing my BSc thesis right now, and the point of the thesis is to predict the bound states of two-nucleon systems (one bound, others not) by treating the problem as a simple QM two body problem. With a potential that only cares about distance (the potential is spherically symmetric), the problem reduces to solving the radial Schrödinger equation, which is essentially the same problem as solving a 1D Schrödinger equation (with an "effective potential"). I have a numerical algorithm that can solve 1D Schrödes. I was thinking that I would use the one-pion exchange potential (OPEP) to represent the nuclear force, but later I realized that it actually has a tensor component. So then I decided to go with the simple Yukawa potential... but then I realized that that actually does not differentiate between nucleons at all (no spin or isospin dependence at all) and would hence give the same energies for dineutron and deuteron. Using the Yukawa potential is still a backup plan I suppose, but if I use it, I can't demonstrate how the exclusion princible together with the NN interaction's spin-dependence prevents the dineutron (and hence also the diproton) from being bound, which is the whole point of the thesis.

And that concludes the general description of the problem. Now let's get to the specifics! (Sorry about using pictures instead of the equation editor; I'm new and I don't know how that stuff works yet.)
  • Would it make sense to average OPEP over all directions to ignore the angle dependence and hence get a spin-dependent spherically symmetric potential? If yes, how?
Here's what OPEP looks like (source: https://www.physics.umd.edu/courses/Phys741/xji/chapter6.pdf):

lRmebUf.png


If I've understood correctly, the dot product of the two spin matrices is either 1 (for a triplet spin) or -3 (for a singlet spin). Earlier in the same paper we also see this:

DSCWE3r.png


... so I can also understand what the product thing with the taus is! I'm still not confident that I understand isospin though, so let me just confirm a few things: the deuteron can have either T = 0 or T = 1, but diproton and dineutron can only have T = 1, right? Is that the way it works?

And the deuteron bound state is with T = 0 and S = 1, so that (τ1.τ2) = -3, and (σ1.σ2) = 1, right?
  • Can I just set the tensor part of OPEP to zero?
In Krane's book Introductory Nuclear Physics on page 112 there is a very similar equation given for OPEP. The only difference as far as I can tell is that the version I presented earlier is in natural units... and Krane's version does not have the tau dot product thing (I have no idea why that is btw). Anyhow, earlier on page 102 of Krane's book it says that the tensor thing S12 "averages to zero over all angles", so I tried setting the term to zero, assuming I'd get the average part of OPEP out the other end... but it resulted in nothing but nonsense, because it makes OPEP positive for the triplet state and negative for the singlet state. Am I missing something or is the whole idea of setting the tensor part to zero stupid?

Also, setting S12 to zero makes OPEP specifically depend on (τ1.τ2)*(σ1.σ2), which is more than dubious since it works out the same for the deuteron ground state (T = 0, S = 1) as for dineutron and diproton (T = 1, S = 0).

If I can't make OPEP work... then what?

For example, is there some spin-dependent term I could for just add with the simple Yukawa potential?

And if none of this works out, then what kind of reasoning am I going to use to show that the dineutron is not bound, if I've just shown independently of spin and isospin that the deuteron has a bound state?

I've been spending way too much time on trying to figure this one out. I should already be quite a bit into writing the damn thesis already but this problem is stumping me hard. Any advice would be greatly appreciated. I'm all ears, and thanks in advance!
 

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  • #2
Why does my post strikethrough parts of itself on its own?

EDIT: Fixed it. Still have no idea what caused it tho...
 

1. What is a spherically symmetric spin-dependent NN potential?

A spherically symmetric spin-dependent NN potential refers to a type of potential energy function used in nuclear physics to describe the interactions between two nucleons (protons or neutrons). This potential takes into account the spin of the nucleons, as well as their relative distance from each other, resulting in a spherical shape.

2. Why is a spherically symmetric spin-dependent NN potential important?

This type of potential is important because it accurately describes the strong nuclear force between nucleons, which is crucial for understanding the behavior of atomic nuclei. It is also used in theoretical calculations and simulations in nuclear physics research.

3. How is a spherically symmetric spin-dependent NN potential calculated?

The potential is typically calculated using a combination of experimental data and theoretical models. The interaction between two nucleons is described by a potential energy function, which is then fitted to match experimental data. This potential is then used in simulations to study the behavior of nucleons in a nucleus.

4. What are the limitations of a spherically symmetric spin-dependent NN potential?

One limitation is that it does not take into account the effects of higher order terms in the nuclear force, such as three-body interactions. It also assumes that the nucleons are point particles, which may not accurately reflect their true nature. Additionally, the potential may vary depending on the specific types of nucleons involved.

5. How is a spherically symmetric spin-dependent NN potential used in nuclear physics research?

This type of potential is used in a variety of ways, such as in simulations of nuclear reactions, calculations of nuclear properties, and studies of nuclear structure. It is also used in theoretical models to understand and predict the behavior of nucleons in different nuclear environments.

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