I need the proof of squeeze lemma on sequences

  • Thread starter Thread starter singedang2
  • Start date Start date
  • Tags Tags
    Proof Sequences
Click For Summary

Homework Help Overview

The discussion revolves around the proof of the squeeze lemma specifically for sequences, where the original poster seeks clarification on how to adapt the proof of the squeeze theorem to this context.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the necessity of using the epsilon-delta definition of limits and how it applies to sequences. There are inquiries about the application of the squeeze lemma in the context of sequences, and some participants reference the general squeeze theorem.

Discussion Status

The discussion is ongoing, with participants exploring the definitions and implications of limits in sequences. Some guidance has been provided regarding the epsilon definition, but there is no explicit consensus on the proof approach yet.

Contextual Notes

The original poster specifies a distinction between the proof of the squeeze lemma for sequences and the regular squeeze theorem, indicating a need for a tailored explanation.

singedang2
Messages
25
Reaction score
0
urgent! i need the proof of squeeze lemma on sequences

if y_n \leq x_n \leq z_n and y_n \rightarrow p and z_n \rightarrow p

then x_n \rightarrow p

Note. I'm not looking for the proof of the regular squeeze theorem. this is supposed to be a proof adapting the proof of squeeze theorem onto the sequences.
 
Physics news on Phys.org
What have you tried? You'll need to use the epsilon delta definition of the limit.
 
how am i suppose to apply this into the sequences?
 
Do you know the definition of the limit of a sequence? It's very similar in form to the epsilon delta definition used for functions.
 
If a_n\le b_n\le c_n and \lim a_n= \lim c_n= L then lim b_n= L.

Since lim a_n= L, then, given any \epsilon for some N1, if n> N1, |a_n- L|< \epsilon. Since lim c_n= L, given any \epsilon for some N2, if n> N2, |c_n- L|< \epsilon. If n> larger of (N1, N2) what can you say about both a_n and c_n. What does that tell you about c_n?
 

Similar threads

Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 8 ·
Replies
8
Views
5K