I need the two elements with the greatest volume in a data set

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SUMMARY

The discussion centers on calculating the volume of elements in large data sets represented as pairs of coins and amounts, specifically focusing on identifying the two elements with the greatest volume. The calculations involve using weighted averages, with examples provided for sets such as {10 & 11, 9 & 7, 8 & 9, 4 & 5, 3 & 1} yielding a volume of 2.04, and {1 & 1, 2 & 2, 3 & 12, 4 & 4, 5 & 3} resulting in 3.0921. Participants suggest the need for integrals or summations to accurately determine volumes and locations of maximum values, indicating a preference for quadratic functions for further analysis.

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  • Understanding of weighted averages in data analysis
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tunage
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I have very large data sets:
coins & amount
i.e. {10 & 11, 9 & 7, 8 & 9, 4 & 5, 3 & 1} graphed would show greater volume to the left side while {1 & 0, 2 & 3, 2 & 1, 4 & 6, 9 & 10} would reflect greater volume on the right, and {1 & 4, 2 & 3, 12 & 10, 4 & 4, 3 & 2} would reflect a surge in the middle of the data set.
I need to calculate the volume and know the location of the two elements that have the greatest volume.
 
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tunage said:
I have very large data sets:
coins & amount
i.e. {10 & 11, 9 & 7, 8 & 9, 4 & 5, 3 & 1} graphed would show greater volume to the left side while {1 & 0, 2 & 3, 2 & 1, 4 & 6, 9 & 10} would reflect greater volume on the right, and {1 & 4, 2 & 3, 12 & 10, 4 & 4, 3 & 2} would reflect a surge in the middle of the data set.
I need to calculate the volume and know the location of the two elements that have the greatest volume.

If I understand your requirements correctly I think the following would be OK.

For the first set $\frac{1\times 10\times 11+2\times 9\times 7+3\times 8\times 9+4\times 4\times 5+5\times 3\times 1}{ 10\times 11+9\times 7+8\times 9+4\times 5+3\times 1}=2.04..$

The 2.04 indicates your "greater volume to the left side".

This may be of interest: http://archives.math.utk.edu/visual.calculus/5/work.2/
 
M R said:
If I understand your requirements correctly I think the following would be OK.

For the first set $\frac{1\times 10\times 11+2\times 9\times 7+3\times 8\times 9+4\times 4\times 5+5\times 3\times 1}{ 10\times 11+9\times 7+8\times 9+4\times 5+3\times 1}=2.04..$

The 2.04 indicates your "greater volume to the left side".

This may be of interest: http://archives.math.utk.edu/visual.calculus/5/work.2/

Thank you for your response.
I tried it with the 3rd example and I don't see where it would help.
--> (1*1*4+2*2*3+3*12*10+4*4*4+5*3*2)/(1*4+2*3+12*10+4*4+3*2)
ans =
3.0921
But more importantly I need the element location.
Yes, I am pretty sure I need an integral or a summation for the volume but I think I am going to need quadratics for my second max and probably my first.
 
Last edited:
tunage said:
Thank you for your response.
I tried it with the 3rd example and I don't see where it would help.
--> (1*1*4+2*2*3+3*12*10+4*4*4+5*3*2)/(1*4+2*3+12*10+4*4+3*2)
ans =
3.0921
But more importantly I need the element location.
Yes, I am pretty sure I need an integral or a summation for the volume but I think I am going to need quadratics for my second max and probably my first.

If your locations are 1,2,3,4 and 5 then a result of 3.09 is pretty much your "surge in the middle".

Still, I'm not sure that what I'm suggesting is what you need.
 
M R said:
If your locations are 1,2,3,4 and 5 then a result of 3.09 is pretty much your "surge in the middle".

Still, I'm not sure that what I'm suggesting is what you need.

That is a very interesting math hack.
I am running some test on it now.
 
tunage said:
That is a very interesting math hack.
I am running some test on it now.
Works perfect. It does everything I need it to do. I don't even need the second max because of how the numbers work.

Thank you VERY much!

I think I remember seeing this back in Physics.
 

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