I understanding a concept about motor efficiency

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SUMMARY

The discussion focuses on calculating the power required for a motor to accelerate a 1250 kg elevator to a speed of 2 m/s within 3 seconds, considering a motor efficiency of 0.80. Key equations include Newton's second law (F = ma), the relationship between power and work (P = dW/dt), and the efficiency equation (P_out = η P_in). The participants emphasize the importance of accounting for gravitational potential energy when the elevator moves vertically, and clarify that the weight should be referred to as mass (kg instead of Kg).

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic principles of power and work in physics
  • Knowledge of motor efficiency concepts
  • Familiarity with gravitational potential energy calculations
NEXT STEPS
  • Calculate the required power using the formula P = F * v, incorporating motor efficiency
  • Explore the implications of gravitational potential energy in vertical motion scenarios
  • Review the concepts of kinetic energy and its relation to motor power requirements
  • Investigate the effects of varying elevator speeds on power calculations
USEFUL FOR

Engineering students, physics enthusiasts, and professionals involved in elevator design or motor efficiency optimization will benefit from this discussion.

pizzamakeren
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Homework Statement
I need help solving a problem about motor efficiency and an elevator
Relevant Equations
Weight of elevator: 1250Kg. Speed after 3 seconds: 2m/s +/- 0,10m. Motor efficiency: 0,80
I have tried to solve a problem about the amount of watts a motor needs to recive if i want an elevator of 1250Kg to move at a speed of 2m/s +/- 0,10m/s after 3 seconds. The motor has an efficiency of 0,80. I've tried looking at my teachers uni recording, but it doesn't seem to explain this part very well. Could someone with knowledge about this try to teach me how i should handle this task? I know that the motor efficiency makes it so that i need more watts, as 20% of the energy put into the motor vanishes into other forms of energy.
 
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pizzamakeren said:
Homework Statement:: I need help solving a problem about motor efficiency and an elevator
Relevant Equations:: Weight of elevator: 1250Kg. Speed after 3 seconds: 2m/s +/- 0,10m. Motor efficiency: 0,80

I have tried to solve a problem about the amount of watts a motor needs to recive if i want an elevator of 1250Kg to move at a speed of 2m/s +/- 0,10m/s after 3 seconds. The motor has an efficiency of 0,80. I've tried looking at my teachers uni recording, but it doesn't seem to explain this part very well. Could someone with knowledge about this try to teach me how i should handle this task? I know that the motor efficiency makes it so that i need more watts, as 20% of the energy put into the motor vanishes into other forms of energy.
Try to sort out your problem on the one hand, and the tools you have available on the other hand.m That solves three quarters of this forum's exercises. That's what the template is intended for. So:

Homework Statement:: how much power is needed to accelerate 1250 kg to 2 m/s in 3 seconds at 80 % efficiency

Relevant Equations:: $$\begin {align*}
F &= ma\\
v &= v_0 + at \\
dW &= \vec F\cdot d\vec s \\
P&={dW\over dt} \\
P_{\rm out} &= \eta P_{\rm in}
\end{align*}$$
 
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What is the meaning of +/- 0,10m?
 
It means it varies, Sometimes it's 1,9m/s and sometimes it's 2,1m/s
 
pizzamakeren said:
It means it varies, Sometimes it's 1,9m/s and sometimes it's 2,1m/s
Thank you.
Can you work some calculation based on post #2?
 
pizzamakeren said:
It means it varies, Sometimes it's 1,9m/s and sometimes it's 2,1m/s
Interesting. Will it never never never be 2.3 m/s or more ?

But since you probably want only one motor, you'll have to pick a single value :smile: .
 
BvU said:
Interesting. Will it never never never be 2.3 m/s or more ?

But since you probably want only one motor, you'll have to pick a single value :smile: .
it's going to stay at 2m/s after 3 seconds
 
Lnewqban said:
Thank you.
Can you work some calculation based on post #2?
F = 825
Im not sure what v0, Dw, ds, or dt means so i can't calculate the rest
 
@pizzamakeren, assuming the elevator is moving vertically, then as well as kinetic energy, you may be expected to consider the gain/loss in gravitational potential energy (depending on which direction elevator moves).

Also (being pedantic) there are 2 mistakes in the statement:
“Weight of elevator: 1250Kg“
 
  • #10
Steve4Physics said:
@pizzamakeren, assuming the elevator is moving vertically, then as well as kinetic energy, you may be expected to consider the gain/loss in gravitational potential energy (depending on which direction elevator moves).

Also (being pedantic) there are 2 mistakes in the statement:
“Weight of elevator: 1250Kg“
Mass of elevator
 
  • #11
pizzamakeren said:
Mass of elevator
The other mistake is Kg should be kg.
'k' means kilo (=1000).
'K' means kelvin (unit of temperature).
 

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