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I-V Plot and load line

  1. Apr 17, 2015 #1
    • thread will open for replies once a relevant screenshot is available
    1. The problem statement, all variables and given/known data
    Plot the iA vs. vA characteristics for the nonlinear network shown in Figure 4.49. Assume the diode is ideal.

    The nonlinear network from part (a) is connected as shown in Figure 4.50. Draw the load line on your v i characteristics from part (a), and find iT

    physicspicture.jpg

    2. Relevant equations
    V=IR


    3. The attempt at a solution

    For part A I have separated the problem into two states diode on and diode off. When the diode is off the voltage Va (which I have control over) should be Va=Ia(1000)

    When the diode is on, then the voltage I have is Va=Ia(500)

    This transition occurs at Va= 1V so the graph looks like two lines with a change in slope at Ia=.001.

    There is no solutions manual for this so I was wondering if I am on the right track. This makes sense to me since when the diode is on we have a linear circuit as well as when the diode is off.



    My other attempt (at the load line) has been futile as I don't really know how to go about doing this
     
    Last edited by a moderator: Apr 17, 2015
  2. jcsd
  3. Apr 18, 2015 #2

    NascentOxygen

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    Staff: Mentor

    The loadline is set by the circuit external to the load, i.e., the circuit external to the NLD block. So in Fig 4.50 the loadline is the V-I plot determined by the source and the 1kΩ resistor.
     
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