Ice cube into water/thermal equilibrium

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Homework Help Overview

The problem involves a glass containing ice and water, where participants are tasked with determining the equilibrium state after heat exchange between the two substances. The context includes concepts from thermodynamics, specifically heat transfer and phase changes.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss whether the volume of the glass is relevant to the problem and question the necessity of using the heat of fusion in their calculations. Some express confusion about the final temperature and the melting of ice.

Discussion Status

The discussion is ongoing, with various interpretations being explored. Some participants have provided calculations and insights, while others have confirmed or questioned the findings. There is no explicit consensus on the final outcome, but guidance has been shared regarding the heat transfer process.

Contextual Notes

Participants note that the problem neglects heat transfer to the environment and raises questions about the assumptions made regarding the masses and temperatures involved.

farmerburns
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Homework Statement



A 400 cm3 glass is filled with 100 g of ice at 0°C and 170 g of water at 25°C.

Characterize the content of the glass after equilibrium has been reached. Neglect heat transfer to and from the environment.

_ g (mass of water)
_ g (mass of ice)
_°C (equilibrium temperature)



Homework Equations



(dQ)=mc(dT)
specific heat of water= 1.00 (cal/gK)
latent heat of fusion for ice= 79.6 (cal/g)
specific heat of ice= 0.5 (cal/gK)?




The Attempt at a Solution



I have tried this as many ways as I can think of. First off, is volume even an issue? Second, do I need to use heat of fusion to find the final temp.? I feel very lost.
 
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m(w)*C*(T2-T1) = m(i)*L + m(i)*T1
The volume of the glass is given to make shure that water will not spill out of the glass when ice and water is filled in the glass.
 
rl.bhat said:
m(w)*C*(T2-T1) = m(i)*L + m(i)*T1
The volume of the glass is given to make shure that water will not spill out of the glass when ice and water is filled in the glass.

Using the given equation I get T2=71.8C. Seems a bit high to me. Any other suggestions? I used intial temp. of water=25C, and initial temp of ice=0C.
 
Amount of heat needed to melt the ice = 100*79.6 cal.
Heat lost by the water to reach 0 degree C is = 175*25 cal, which is less than the above. So the ice does not melt completely. Final temperature of the mixture is zero.
 
yes, you are right, thank you. I figured it out today with some help.
 

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