# Ice Cube Pressure on Incline: Solve for F

• brncsfns5621
In summary, the ice cube, with a density of 917 kg/m^3, is sliding down a frictionless incline at a 16 degree angle. The sides of the cube are each 0.75 m in length. To determine the pressure exerted by the cube on the incline, we can use the equation P = F/A, where F is the force and A is the contact surface area. Since the force is equal to mass multiplied by acceleration, we can also use F = ma, where m is the mass of the cube and a is the acceleration. However, to solve for the force, we also need to know which forces are acting on the cube and their components. One force is in the direction of
brncsfns5621
An ice cube, p = 917 kg/m^3, is sliding down a 16 degree frictionless incline. The sides of the cube each have a length of .75 m. What pressure does the cube exert on the incline?

P = F / A
= F / .75^3
= F / .42

F = ma
= 917 * a

I am having a problem figuring out the Force for this equation. I know it's simple, just can't put my finger on it. Please help.

Which force is acting on the cube? One component of that force is in the direction of the motion of the cube, and one is perpendicular to the contact surface (m^2 !) of the cube and the incline.

To solve for the force (F), we need to use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a). In this case, the mass of the ice cube is given as 917 kg/m^3 and the acceleration is due to gravity, which is 9.8 m/s^2. Therefore, the force (F) can be calculated as:

F = m * a
= 917 kg/m^3 * 9.8 m/s^2
= 8986.6 N

Now, to find the pressure (P) exerted by the ice cube on the incline, we can use the formula P = F / A, where A is the area of contact between the ice cube and the incline. Since the cube is sliding down the incline, the area of contact is equal to the length of one side of the cube, which is 0.75 m. Therefore, the pressure exerted by the ice cube on the incline is:

P = 8986.6 N / 0.75 m^2
= 11,982.1 Pa

Therefore, the ice cube exerts a pressure of 11,982.1 Pa on the incline as it slides down. It is important to note that this calculation assumes a frictionless incline and does not take into account any external forces acting on the ice cube.

## 1. What is the formula for calculating ice cube pressure on an incline?

The formula for calculating ice cube pressure on an incline is F = mgsinθ, where F is the force exerted by the ice cube, m is its mass, g is the acceleration due to gravity, and θ is the angle of the incline.

## 2. How does the angle of the incline affect the pressure of an ice cube?

The angle of the incline affects the pressure of an ice cube by changing the component of the force of gravity acting on the ice cube. As the angle increases, the force of gravity acting on the ice cube also increases, resulting in a higher pressure.

## 3. How does the mass of the ice cube affect its pressure on an incline?

The mass of the ice cube directly affects its pressure on an incline. As the mass increases, the force exerted by the ice cube also increases, resulting in a higher pressure on the incline.

## 4. What is the unit of measurement for ice cube pressure on an incline?

The unit of measurement for ice cube pressure on an incline is Newtons (N). This unit represents the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared.

## 5. Can the formula for calculating ice cube pressure on an incline be applied to other objects?

Yes, the formula for calculating ice cube pressure on an incline can be applied to other objects as long as they have a known mass and are subject to the force of gravity at an angle. This formula is commonly used in physics to calculate the pressure of an object on an incline or ramp.

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