- #1

Carpetfizz

- 13

- 0

## Homework Statement

## Homework Equations

$$mgh = \frac{1}{2}v^2$$

## The Attempt at a Solution

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I'm working on a). I tried using conservation of energy to get v.

$$mg(c+b) = \frac{1}{2}v^2$$

$$v = \sqrt{2g(c+b)}$$

After this I'm stuck. In order to get distance from knowing the velocity, we must know time which is question b). My friend said its possible to solve this problem using forces. Since there are no angles given in this problem, I'm assuming we convert sin and cos quantities into their equivalent ratios which we know? Even then, we will have the net force, but we can't get distance from acceleration without knowing the time.k