Ice cube sliding off metal roof

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1. Dec 9, 2016

Carpetfizz

1. The problem statement, all variables and given/known data

2. Relevant equations

$$mgh = \frac{1}{2}v^2$$

3. The attempt at a solution

I'm working on a). I tried using conservation of energy to get v.

$$mg(c+b) = \frac{1}{2}v^2$$

$$v = \sqrt{2g(c+b)}$$

After this I'm stuck. In order to get distance from knowing the velocity, we must know time which is question b). My friend said its possible to solve this problem using forces. Since there are no angles given in this problem, I'm assuming we convert sin and cos quantities into their equivalent ratios which we know? Even then, we will have the net force, but we can't get distance from acceleration without knowing the time.k

2. Dec 9, 2016

TJGilb

You say you tried to use conservation of energy to get v, but I feel I should point out that your equation is wrong. If you started at rest and define zero potential at the ground, then it should be $mgh=\frac 1 2 mv^2$, in which case the m will cancel from both sides (hence why it says your answer will be independent of mass) giving you $gh=\frac 1 2 v^2$.

Edit: Nvm, your answer looks fine, it must be just a typo.

3. Dec 9, 2016

TJGilb

So, you have your velocity. You also have the direction of that velocity, you just don't realize it. Try forming a triangle out of b and d.

4. Dec 9, 2016

haruspex

@Carpetfizz has calculated the velocity at point C, not point B.

Carpetfizz, the velocity at C is not interesting. Treat the problem in two stages. First find the state of things at point B: velocity and time to get there.

5. Dec 9, 2016

TJGilb

Good catch, I didn't notice that.