Identities for solving log questions

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Homework Help Overview

The discussion revolves around logarithmic identities and their application in solving logarithmic expressions. Participants explore various forms of logarithmic equations, particularly focusing on expressions like (loga b)² and (loga b)(loga c), and question the existence of identities that could simplify these forms.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants express uncertainty about the existence of identities for specific logarithmic expressions and seek clarification on how to approach solving them. Some suggest substituting variables to simplify the problem, while others question the assumptions made in the application of logarithmic identities.

Discussion Status

The discussion is ongoing, with participants sharing insights and suggestions for approaching logarithmic problems. Some guidance has been offered regarding variable substitution and the implications of different cases in inequalities, but no consensus has been reached on a definitive method for all types of logarithmic expressions.

Contextual Notes

Participants mention constraints related to homework rules and the need to solve problems involving variables without the use of calculators. There is also a recognition of potential issues with approximation in calculations.

  • #91
Hi Pranav-Arora! :smile:

Pranav-Arora said:
Thanks!It worked! :smile:

My next question:-

\log_3\frac{|x^2-4x|+3}{x^2+|x-5|} \ge 0

Hmm, that's not a question - it's a problem.
What is your question? :wink:

I suspect that the log should bother you no more by now, nor the matter of the domain of the log function.

The only new thing is the absolute value function...
And I'm not sure whether you fully understand when an inequality inverts and how exactly...

Perhaps show a few steps...?
 
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  • #92
I like Serena said:
Hi Pranav-Arora! :smile:



Hmm, that's not a question - it's a problem.
What is your question? :wink:

I suspect that the log should bother you no more by now, nor the matter of the domain of the log function.

The only new thing is the absolute value function...
And I'm not sure whether you fully understand when an inequality inverts and how exactly...

Perhaps show a few steps...?

When i tried to solve it, i wasn't able to go further than this:-

\frac{|x^2-4x|+3}{x^2+|x-5|} \ge 1

I am not able to figure out what should i do next? :confused:
 
  • #93
Pranav-Arora said:
When i tried to solve it, i wasn't able to go further than this:-

\frac{|x^2-4x|+3}{x^2+|x-5|} \ge 1

I am not able to figure out what should i do next? :confused:

What would happen if you multiplied left and right by the denominator?

Can you separate this in a number of cases for x?
That is, for instance, what would the signs of the absolute values be if x > 5?
For which values of x would one or the other absolute value invert its sign?
 
  • #94
Pranav-Arora said:
When i tried to solve it, i wasn't able to go further than this:-

\frac{|x^2-4x|+3}{x^2+|x-5|} \ge 1

I am not able to figure out what should i do next? :confused:

What would happen if you multiplied left and right by the denominator?

Can you separate this in a number of cases for x?
That is, for instance, what would the signs of the absolute values be if x > 5?
For which values of x would one or the other absolute value invert its sign?
 
  • #95
I like Serena said:
What would happen if you multiplied left and right by the denominator?

Can you separate this in a number of cases for x?
That is, for instance, what would the signs of the absolute values be if x > 5?
For which values of x would one or the other absolute value invert its sign?

Absolute values are positive only...so why are you asking me "what would the signs of the absolute values be if x > 5?" :confused:
 
  • #96
Pranav-Arora said:
Absolute values are positive only...so why are you asking me "what would the signs of the absolute values be if x > 5?" :confused:

What I meant is that you can write an absolute value without the vertical bars if you put the appropriate sign before it in combination with a domain restriction.

For instance:
|x-5| = (x-5) if x > 5
|x-5| = -(x-5) if x < 5
 
  • #97
Look at the denominator. Can it be negative?

ehild
 

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