Identities sin, cos, tan etc. stuff

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Homework Help Overview

The discussion revolves around simplifying the expression \(\frac{\cos x}{1+\sin x} + \frac{1+\sin x}{\cos x}\), which involves trigonometric identities and algebraic manipulation.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore various algebraic manipulations, including multiplying fractions by conjugates and expanding numerators. There are questions about the validity of certain expansions and simplifications.

Discussion Status

Some participants have provided guidance on expanding and simplifying the expression, while others express confusion about specific steps and the correctness of certain expansions. There is an ongoing exploration of how to correctly manipulate the terms to reach a desired form.

Contextual Notes

Participants question the accuracy of algebraic transformations and the assumptions made during simplification. There is a focus on ensuring that each step adheres to algebraic principles without making unwarranted assumptions.

UltimateSomni
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Homework Statement



((cos x)/(1+sin x))+((1+sin x)/(cos x))

Homework Equations

2012-03-05_12-13-36_59.jpg

The Attempt at a Solution



multiplied the left equation by (cos x)/(cos x) and the right fraction by (1+sin x)/(1+sin x)

get ((cosx)^2 +(1+sinx)^2) / (1+sinx) (cos x)

and I have no idea where to go from here
 
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UltimateSomni said:

Homework Statement



((cos x)/(1+sin x))+((1+sin x)/(cos x))
What are you trying to do, simplify the expression above?
UltimateSomni said:

Homework Equations




2012-03-05_12-13-36_59.jpg



The Attempt at a Solution



multiplied the left equation by (cos x)/(cos x) and the right fraction by (1+sin x)/(1+sin x)

get ((cosx)^2 +(1+sinx)^2) / (1+sinx) (cos x)

and I have no idea where to go from here
 
Yes, the answer being 2 sec x
 
Expand the numerator and simplify.
((cosx)^2 +(1+sinx)^2) / (1+sinx) (cos x)
 
(1-sinx^2) +1 + sinx +1 - sin x

(1- sinx^2) +2 / (1+sin x)(cos x)

I don't see how that helps
 
Mark44 said:
Expand the numerator and simplify.
((cosx)^2 +(1+sinx)^2) / (1+sinx) (cos x)

UltimateSomni said:
(1-sinx^2) +1 + sinx +1 - sin x
The only thing you did that makes sense is replacing cos2(x) with 1 - sin2(x). I don't get what you did go go from (1 + sin(x))2 to 1 + sin(x) + 1 - sin(x).

Mark44 said:
(1- sinx^2) +2 / (1+sin x)(cos x)

I don't see how that helps
 
Then what simplifying is there to do?
 
Apparently I wasn't clear. (1 + sin(x))2 ≠ 1 + sin(x) + 1 - sin(x), which seems to be what you're saying.

The "simplifying" that you need to do is to expand (1 + sin(x))2 to something it is actually equal to.
 
Okay it equals (1+sinx)(1-sinx)
still not way to get to 2secx
 
  • #10
Because that's wrong, too. (1 + sin(x))2 ≠ (1+sinx)(1-sinx), if that's what you're saying.

How do you expand (1 + x)2? This is a similar kind of problem.
 
  • #11
Okay it equals (1+sinx)(1+sinx)
still no way to get to 2secx
 
  • #12
UltimateSomni said:
Okay it equals (1+sinx)(1+sinx)

Expand the expression: apply distributivity to work out the brackets.
 
  • #13
All right got it
 

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