- #1

chwala

Gold Member

- 2,673

- 352

- Homework Statement
- See attached

- Relevant Equations
- Mechanics

Going through this ( Revision) A salways your insights are quite helpful.

I would like to go through all these questions; i will start with (5),

##\left( \dfrac {x} {y} \right)## = ##\left( \dfrac {10 \cos 40^0} {10 \sin 40^0} \right)## + ##\left( \dfrac {4 \cos 150^0} {4\sin 150^0} \right)## + ##\left( \dfrac {6 \cos 260^0} {6 \sin 260^0} \right) ## = ##\left( \dfrac {7.66} {6.43} \right) ## + ##\left( \dfrac {-3.464} {2} \right)## + ##\left( \dfrac {-1.042} {-5.91} \right) ## =

##\left( \dfrac {3.154} {2.52} \right)##

##R = \sqrt {3.154^2 + 2.52^2} = \sqrt {16.3} = 4.03## N

For direction,

##\tan^{-1} \dfrac{2.52}{3.154} = tan^{-1} 0.79898 = 38.6^0## anticlockwise from the x-axis.

I would like to go through all these questions; i will start with (5),

##\left( \dfrac {x} {y} \right)## = ##\left( \dfrac {10 \cos 40^0} {10 \sin 40^0} \right)## + ##\left( \dfrac {4 \cos 150^0} {4\sin 150^0} \right)## + ##\left( \dfrac {6 \cos 260^0} {6 \sin 260^0} \right) ## = ##\left( \dfrac {7.66} {6.43} \right) ## + ##\left( \dfrac {-3.464} {2} \right)## + ##\left( \dfrac {-1.042} {-5.91} \right) ## =

##\left( \dfrac {3.154} {2.52} \right)##

##R = \sqrt {3.154^2 + 2.52^2} = \sqrt {16.3} = 4.03## N

For direction,

##\tan^{-1} \dfrac{2.52}{3.154} = tan^{-1} 0.79898 = 38.6^0## anticlockwise from the x-axis.

Last edited by a moderator: