1. The problem statement, all variables and given/known data A) Calculate the electric potential at point A. B) If a small charged particle with a mass m=5.0 mg and charge q=7.0 nC is released from rest at point A, what will be its final speed vf 2. Relevant equations V=Kq/r Uelec=qV Uelec=1/2mv2 3. The attempt at a solution A) I calculated V for each point. V=(Kq1/r1)+(Kq2/r2)+(Kq3/r3) V=[(9x109)(2x10-9)/0.03]+[(9x109)(2x10-9)/0.04]+[(9x109)(2x10-9)/0.05] V=600+450+360 V=1410 For part A, I converted all my nanocoulombs (nC) to Coulombs (C), as well as my centimeters (cm) to meters (m) before plugging them into my equation. ________________________________________________________________________________________ B) In order to calculate velocity (v), I need to calculate potential energy (Uelec). Uelec=qV Uelec=(7x10-9)(1410) Uelec=9.87x10-6 Again, I convert the 7.0 nC into Coulombs for the 1st half of part B Now I solved for velocity (v) after converting mass from mg to kg: Uelec=1/2mv2 9.87x10-6=1/2(5x10-6)(v2) v2=1/2(5x10-6)(9.87x10-6) v2=2.4675x10-11 I then took the square root of both sides v=5x10-6 m/s It's asking for an assessment of the problem. "How does the velocity compare with a typical bullet's velocity, vbullet=120 m/s?" I'm not sure there is even anything there to compare. With the velocity of the particle at v=0.000005 m/s, and the velocity of a typical bullet at v=120 m/s, the particle is substantially slower than the average bullet. So I must be doing something wrong when there is nothing there to compare.