If each letter stands for a number from 0 to 9 (and different letters stand for different
numbers), find the numerical value of each letter in this addition:
The Attempt at a Solution
(1) N + D = R
(2) I + I = E ----> I = E/2, which means E must be even
(3) R = E
These were my initial conjectures. However, I now feel that they are wrong. At first, I thought that there was no carrying over of digits--which would be a helpful fact--; then I realized that D was in the 1000's place, which implies that there must have been some carrying over.
Could someone help me?
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