If each orbital can hold a maximum of 3 electrons

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Discussion Overview

The discussion revolves around a hypothetical question regarding the maximum number of electrons that can be held in orbitals, specifically questioning the implications of each orbital holding a maximum of 3 electrons. Participants explore the consequences of this scenario on the number of elements in the 4th period of the long form of the periodic table.

Discussion Character

  • Homework-related
  • Debate/contested

Main Points Raised

  • One participant questions the validity of the premise, stating there are no orbitals that can hold a maximum of 3 electrons, suggesting that maximum electron capacity is typically even due to spin pairing.
  • Another participant posits that the question is hypothetical and does not reflect actual atomic structure.
  • A different viewpoint suggests that the question is intended to develop critical thinking skills rather than to align with factual atomic behavior.
  • One participant proposes starting the solution by considering the filled electron configurations of noble gases to determine the number of elements preceding them.
  • Another participant clarifies that the 4th period involves filling the 4s, 3d, and 4p orbitals, encouraging calculations based on the hypothetical scenario.
  • A hint is provided that the first period of the periodic table would contain three elements if each orbital could hold 3 electrons, suggesting a method for analyzing the number of elements in subsequent periods.

Areas of Agreement / Disagreement

Participants express disagreement regarding the premise of the question, with some asserting it is hypothetical and not grounded in established atomic theory. There is no consensus on how to approach the problem due to the foundational disagreement on the premise itself.

Contextual Notes

The discussion highlights the limitations of the hypothetical scenario, including the assumption that orbitals can hold 3 electrons, which contradicts established principles of electron configuration and quantum mechanics.

xiphoid
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Homework Statement


If each orbital can hold a maximum of 3 electrons, the number of elements in the 4th period of long form of periodic table will be?


Homework Equations


?


The Attempt at a Solution


I am not able to decide from where should I begin?
 
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hi xiphoid! :smile:

i don't understand the question …

there are no orbitals which hold a maximum of 3 electrons :confused:

(the maximum would always be even, anyway … spin-ups matching spin-downs)

what exactly is the question, and the background to it?​
 


I bet it is a hypothetical question. That doesn't mean it makes sense.
 


This question is just to develop the thinking skill of the student!
It does not/ never is related to the original/factual happening around or perhaps inside the nucleus.
From where should i start.
I guess, the moment i get the completely filled configuration of noble gas, the number of elements preceding to them would be the answer, but again from where to start?
By taking the default configuration of element in the mentioned period?
Borek said:
I bet it is a hypothetical question. That doesn't mean it makes sense.
 
Yep this IS hypothetical. 4th Period means that electrons are being filled in specifically, 4s, 3d, 4p orbitals.

Calculate the number of electrons you can fill. Try.
 
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Here is a hint, the first period of the long form periodic table contains two elements. This is because each s orbital can only contain 2 electrons. Thus, there can only be two elements; one with Z=1 and the other with Z=2.

In your problem you can have 3 electrons per orbital. So this version of the periodic table must have three elements in the first period with Z=1, Z=2 and Z=3 and the element corresponding to Z=3 is the first noble gas. You can do the same analysis for the second, third and fourth period.
 

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