If f+g is differentiable, then are f and g differentiable too?

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SUMMARY

If the sum of two continuous functions, f and g, is differentiable, it does not imply that both f and g are differentiable. A counterexample is provided with f(x) = x^(1/3) and g(x) = -x^(1/3). While f + g results in the differentiable function y = 0, both f and g are non-differentiable at the origin (x = 0) due to undefined derivatives. This illustrates that differentiability of a sum does not guarantee the differentiability of its components.

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Homework Statement


if f and g are two continuous functions and f+g is differentiable...are f and g differentiable? if not give a counter example!

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I'm thinking not necessarily, but I'm not really sure. Whether a function is differentiable or not depends on whether on not every point on it has a derivative.

So say f is y = x^(1/3), and g is y = -x^(1/3). Both f and g are continuous - the graph of the function is unbroken.

(Technically the definition of continuity is that for every value in the domain the limit from below = limit from above = the value itself but yeah that's not really important.)

f+g is differentiate yeah? f + g just gives y = 0
However, y = x^(1/3) and y = -x^(1/3) are both non differentiable, since at the origin x = 0, the derivative is undefined. You get a divide by zero from memory =P
 


thnx clementc
 


haha no worries! =P
 

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