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Homework Help: If m<n prove that y_1, ,y_m are linear functionals

  1. Mar 4, 2010 #1
    1. The problem statement, all variables and given/known data
    Prove that if m<n, and if [tex]y_1,\cdots,y_m[/tex] are linear functionals on an n-dimensional vector space V, then there exists a non-zero vector x in V such that [tex][x,y_j]=0[/tex] for [tex]j=1,\cdots,m[/tex]. What does this result say about the solutions of linear equations?


    2. Relevant equations

    N/A

    3. The attempt at a solution

    Let [tex]X=\{x_1,\cdots,x_n\}[/tex] be a basis for V.
    By a theorem in the book I know that there exists a uniquely determinet basis X' in V',
    [tex] X'=\{y_1,\cdots,y_n\} [/tex] with the property that [tex][x_i,y_j]=\delta_{ij}[/tex].

    Every [tex]x\in V[/tex] can be written as [tex] x=\xi_1 x_1+\cdots+\xi_n x_n[/tex].
    If we let [tex]j=1,\cdots,m[/tex] we get,
    [tex][x,y_j]=\xi_1[x_1,y_j]+\cdots+\xi_m[x_m,y_j][/tex] and since [tex][x_i,y_j]=\delta_{ij} [/tex], there exists some x such that [tex][x,y_j]=0[/tex].

    The result says that the solution of linear equations consists of a homogeneous solution and a particular solution.

    Any input is very welcome, Thanks!
     
  2. jcsd
  3. Mar 6, 2010 #2
    Gentle bump.
     
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