If our bodies could run on fusion power

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SUMMARY

The discussion centers on the hypothetical scenario of human bodies operating on fusion power, specifically calculating the energy available from converting 0.8% of a 60 kg mass into energy. Using the mass-energy equivalence equation E = mc², the calculation yields approximately 4.32 x 1016 joules of energy. This amount of energy would sustain a human body, requiring 120 watts, for about 3.6 x 1014 seconds. The conversation highlights the simplifications made in the question, as it overlooks the complexities of energy generation and conversion in a biological context.

PREREQUISITES
  • Understanding of mass-energy equivalence (E = mc²)
  • Basic knowledge of physics, particularly energy calculations
  • Familiarity with units of power (watts) and energy (joules)
  • Concept of fusion power and its theoretical implications
NEXT STEPS
  • Research the principles of nuclear fusion and its potential applications in energy generation
  • Explore advanced topics in mass-energy equivalence and its implications in physics
  • Learn about the biological energy requirements of the human body and how they are met
  • Investigate the complexities of energy conversion processes in biological systems
USEFUL FOR

Students of engineering and physics, energy researchers, and anyone interested in the theoretical applications of fusion power in biological systems.

jaredogden
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So I saw someone post this question on facebook and naturally being an Engineering student I'm curious to know now. I haven't done any Physics in a while so I'm not sure how you would tackle this one. The question was:

"The power needed to operate your body is about 120 watts. Suppose your mass is 60kg and your body could run on fusion power. If you could convert 0.8% of you mass into energy, how much energy would be available to run your body and for how long could you operate on fusion power?"

My first instinct was to just take 0.8% of 60 kg to get .48 kg and plug that into the mass-energy equivalence equation to get

E = (.48 kg)(3x1088 m/s)2
E = 4.32x1016 J

then do 4.32x1016 J/120 Watts to get 3.6x1014 second.

I'm not even sure if the mass-energy equivalence equation can be applied to this situation or not. I don't think there is a way to use the nuclear binding energy equations either, however I'm not a physicist and don't know nuclear physics too too well.

Well thanks for any explanations.
 
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Yes that's correct. All the complications as to how the energy would be made are swept under the rug by just saying "convert 0.8% of your mass into energy". All the interesting specifics go away by saying that.
 
I thought so but just wasn't sure. Thanks for the help!
 

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