MHB If S=9999 prove we can find at least 3 students having the same score

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SUMMARY

In the discussion, it is established that if the total score S of 201 students is 9999, there must be at least three students with the same score. This conclusion is derived from the Pigeonhole Principle, which states that if more items are distributed across fewer containers than there are items, at least one container must hold more than one item. The same principle applies to the scenarios where S equals 10101, 10000, and 10100, leading to specific score distributions among the students.

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A={0,1,2,3,4,5,--------,99,100}
201 students are attending a math test ,the score of each student can be
found from set A,if S represents the total scores of all 201 students,please answer
the following questions
(1) if S=9999 prove we can find at least 3 students having the same score
(2) if S=10101 prove we can also find at least 3 students having the same score
(3) if S=10000 and it is known no three students having the same score
,then there must have 1 student having score 100,and 2 students with scores 0
(4) if S=10100 and it is known no three students having the same score
,then there must have 1 student having score 0,and 2 students with scores 100
 
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Albert said:
A={0,1,2,3,4,5,--------,99,100}
201 students are attending a math test ,the score of each student can be
found from set A,if S represents the total scores of all 201 students,please answer
the following questions
(1) if S=9999 prove we can find at least 3 students having the same score
(2) if S=10101 prove we can also find at least 3 students having the same score
(3) if S=10000 and it is known no three students having the same score
,then there must have 1 student having score 100,and 2 students with scores 0
(4) if S=10100 and it is known no three students having the same score
,then there must have 1 student having score 0,and 2 students with scores 100
hint:
with the restriction :
no three students having the same score ,find min(S) and max(S)
 
My attempt:

The task is to assign scores ($0,1,.., ,100$) to $201$ students.

Using the hint from Albert, I proceed as follows:

Given the restriction: No three students have the same score, what is $S_{max}$ and $S_{min}$?

I can assign a score only twice: $2$ x $0$, $2$ x $1$, …, $2$ x $100$. Total sum is $10.100$.

This sum corresponds to exactly $202$ assignments, so we need to subtract just one single score. By taking

the largest and the smallest possible score, we easily find the max/min sum:

Thus:

$S_{min} = 10.100 – 100 = 10.000$ (*)

Subtracting $100$ from the total sum means, we have only one student with score $100$ in the test, and two

students with score $0$ (if not, there would only be $199$ students) – wen $S = S_{min}$. This answers problem (3).$S_{max}= 10.100 – 0 = 10.100$. (**).

Subtracting $0$ from the total sum means, we have only one student with score $0$ in the test and two students

with score $100$, - wen $S = S_{max}$. This answers problem (4).From (*) and (**) we can conclude, that: If $10.000 \le S \le 10.100$ then there are no three students having the same score.

in the group of 201 students. Or the complementary statement: Any sum, $S$, smaller than $S_{min}$

or greater than $S_{max}$ will contain at least a triple score.

This answers problem (1) and (2) In Alberts challenge, and we are done.
 
lfdahl said:
My attempt:

The task is to assign scores ($0,1,.., ,100$) to $201$ students.

Using the hint from Albert, I proceed as follows:

Given the restriction: No three students have the same score, what is $S_{max}$ and $S_{min}$?

I can assign a score only twice: $2$ x $0$, $2$ x $1$, …, $2$ x $100$. Total sum is $10.100$.

This sum corresponds to exactly $202$ assignments, so we need to subtract just one single score. By taking

the largest and the smallest possible score, we easily find the max/min sum:

Thus:

$S_{min} = 10.100 – 100 = 10.000$ (*)

Subtracting $100$ from the total sum means, we have only one student with score $100$ in the test, and two

students with score $0$ (if not, there would only be $199$ students) – wen $S = S_{min}$. This answers problem (3).$S_{max}= 10.100 – 0 = 10.100$. (**).

Subtracting $0$ from the total sum means, we have only one student with score $0$ in the test and two students

with score $100$, - wen $S = S_{max}$. This answers problem (4).From (*) and (**) we can conclude, that: If $10.000 \le S \le 10.100$ then there are no three students having the same score.

in the group of 201 students. Or the complementary statement: Any sum, $S$, smaller than $S_{min}$

or greater than $S_{max}$ will contain at least a triple score.

This answers problem (1) and (2) In Alberts challenge, and we are done.
Thanks lfdahl: well done
 

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