How Much Is the Friction Acting on a Crate Sliding at Constant Velocity?

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When a crate is pushed with a force of 100 N and slides at constant velocity, the friction acting on it also measures 100 N, indicating dynamic equilibrium. This means the net force on the crate is zero, as the applied force is balanced by the frictional force. The discussion clarifies that if the crate experiences no acceleration, the forces must be equal and opposite. One participant initially questioned how a force could be applied if an equal resistance exists but concluded that the scenario described does not allow for movement under those conditions. The key takeaway is that the friction force matches the applied force when an object moves at constant velocity.
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If you push on a crate with a force of 100 N and it slides at constant velocity, how much is the friction acting on the crate?

Consider a crate being pushed horizontally across a factory floor. If it moves at a steady speed in a straight - line path, it is in dynamic equilibrium. This tells us that more than one force acts on the crate. Another force exists likely the force of friction between the crate and the floor. The fact that the net force on the crate equals zero means that the force of fricition must equal and opposite to our pushing force.

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3. 100 N of friction
 
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What exactly is ur question??

U already got ur answer that friction force is 100N as there is no acceleration of crate and all
applied force is canceled by friction to keep body in dynamic equilibrium
 


My question was my answer I thought, but I was thinking if someone was pushing the crate at 100 N and there was 100 N of resistance how would they be pushing it but you answered my thought they wouldn't be.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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