Calculating the Force Needed for Constant Velocity of a 15 kg Crate on a Floor

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SUMMARY

The discussion centers on calculating the horizontal force required to slide a 15 kg crate across a floor at a constant velocity, given a coefficient of kinetic friction of 0.28. The formula used is F = μ * m * g, where μ is the coefficient of kinetic friction, m is the mass of the crate, and g is the acceleration due to gravity (9.8 m/s²). The calculated force is 41.16 N, which rounds to 41.2 N. This calculation has been confirmed as accurate by other participants in the discussion.

PREREQUISITES
  • Understanding of Newton's Second Law (Fnet = ma)
  • Knowledge of friction coefficients, specifically kinetic friction
  • Basic arithmetic operations involving multiplication and rounding
  • Familiarity with gravitational acceleration (9.8 m/s²)
NEXT STEPS
  • Study the implications of varying coefficients of friction on force calculations
  • Learn about static vs. kinetic friction and their applications
  • Explore real-world applications of Newton's laws in physics problems
  • Investigate how mass and gravitational force affect frictional force
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of force calculations involving friction.

Medgirl314
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Homework Statement


A 15 kg crate rests on the floor. The coefficient of kinetic friction between the crate and the floor is 0.28. How much horizontal force is needed to slide the crate across the floor at a constant speed?


Homework Equations



Fnet=ma


The Attempt at a Solution


F=MN
Mmg=.28*15 kg*9.8

41.16 N
For a final rounded answer of 41.2 N.

This answer seems plausible to me, would someone please confirm?

Thanks! :smile:
 
Last edited:
Physics news on Phys.org
Looks right to me.
 
Thank you!
 

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