A turtle crawls along a straight line, which we will call the x-axis with the positive direction to the right. The equation for the turtle's position as a function of time is
x(t)=50.0 cm+(2.00cm/s)t-(0.0625 cm/s^2)t^2
At what time t will the turtle be 10 cm from his initial position for the 1st, 2nd, and 3rd times
s(x)= r + v(t) - gt^2
The Attempt at a Solution
I have solved already for the first and second times for 6.2 and 25.8. I also figure that it takes 32 seconds to reach the initial point. My reasoning would be 32+6.2 giving me 38.2, but that seems to be wrong. Any help please.