- #1
Dhananjay97
- 3
- 0
Member warned about proper use of the template and showing an attempt at solution.
Image distance after passing through lens and mirror
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SUMMARY
The discussion focuses on calculating image distances after light passes through a lens and reflects off a mirror. The lens has a focal length of +77.9 cm, while the mirror has a focal length of -59.0 cm, with a separation distance of 1.00 m. The user initially applied the lens formula 1/f = 1/p + 1/q incorrectly, leading to confusion about the image's position. Correct application of the formula, considering the virtual image created by the mirror, is essential for accurate results.
PREREQUISITES- Understanding of the lens formula: 1/f = 1/p + 1/q
- Knowledge of focal lengths for lenses and mirrors
- Ability to identify virtual and real images in optics
- Familiarity with the concept of image distance and object distance
- Review the lens formula and its applications in optics
- Study the behavior of light rays when passing through multiple optical elements
- Learn about virtual images and their implications in optical systems
- Explore practical examples of lens and mirror combinations in optical devices
Students and professionals in physics, particularly those studying optics, as well as anyone involved in designing or analyzing optical systems with lenses and mirrors.
- #2
JeremyG
- 62
- 16
Post your working here and we'll help you find your mistakes, yeah? We don't provide full solutions here at PF. :)
- #3
Dhananjay97
- 3
- 0
first i started with the object and the lens and substituted the values in the equation 1/f=1/q+1/p since we know focal length of the lens and the object distance, and got 352.489 cm. This put the image to the right side of the mirror. Now the object of the mirror (the image of the lens) is on the same side as the focal point of the mirror so I solved for q again using the same equation and using -252.489 cm as my p (subtracted 100 cm because that was the distance between the lens and mirror). i got - 76.9907cm which meant the image was still to the right of the mirror. from there i followed two approaches:-
1) assume that the image from the image goes straight to the lens and use -176.9907 cm as p to solve for q to get 38.72 cm to the left of the lens
2) assume that the image from the mirror goes through the mirror again solve for the mirror again, using the same equation but the image kept going further to the right.
1) assume that the image from the image goes straight to the lens and use -176.9907 cm as p to solve for q to get 38.72 cm to the left of the lens
2) assume that the image from the mirror goes through the mirror again solve for the mirror again, using the same equation but the image kept going further to the right.
- #4
JeremyG
- 62
- 16
Dhananjay97 said:
This approach is incorrect. The light ray has already reflected off the mirror at that point, and is going towards the lens. It just appears to be coming from behind the mirror (virtual image).
Dhananjay97 said:
Check your working for this step again. I suspect you might have a careless mistake here.
- #5
Dhananjay97
- 3
- 0
you were right! thank you so much
- #6
JeremyG
- 62
- 16
Dhananjay97 said:
Yup, it's my pleasure!
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