Sir, I am posting these questions for the 3rd time as you didn't respond. Please respond. 1)A convergent beam of light is incident on a convex mirror of radius of curvature 60 cm as shown in figure. What is the nature and position of the image formed by it? I solved it in the following way: Let u, v and f be the object distance, image distance and focal length of the convex mirror respectively. Here u = + 10 cm, f = +30 cm 1/u + 1/v = 1/f v = (uf)/(u-f) = (10 x 30)/(10 – 30) = -15 cm Hence the image formed is virtual and 15 cm in front of the mirror. Is it right? 2)A convex mirror of focal length f produces an image (1/n)th of the size of the object. What is the distance of the object from the mirror? I solved it in the following way: Magnification = 1/n = -(v/u) i.e. v = -(u/n) 1/u + 1/v = 1/f 1/u – (n/u) = 1/f By solving I get, u = (1-n)f Are my sign conventions right? Sometimes the diagram may not be clear. So I will try to describe the diagram. A convergent beam of light serves as a virtual object which appears to converge at a distance of 10 cm behind the mirror.