Imaginary number's definition misunderstanding

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The discussion centers on the misunderstanding of imaginary numbers, specifically the definition of i as the square root of -1 and its implications. The user grapples with the relationship between i^2 and -1, questioning why i^2 does not equal 1 when applying the property of radicals. Responses clarify that while i = SQRT(-1), the operations involving square roots differ in the realm of complex numbers compared to real numbers. It is emphasized that the square root has ambiguities in complex arithmetic, and not all properties of real numbers apply. The conversation highlights the importance of understanding these differences to avoid confusion in mathematical operations involving imaginary numbers.
alingy1
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Homework Statement



I'm in this self-learning course. I came on this problem I thought of.

So, i^2=-1.
But, isn't i=sqroot of -1?
If so, the product of the two minus -1 and the square root of that should give 1.

Am I not getting something?
I searched the web with the keywords of my question, but I couldn't find any result...
 
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Is i positive or negative?

The relation i^2 = -1 is the converse of saying i = SQRT(-1). If a = SQRT(b), then a^2 = b.

Then, there are these relations:

i = SQRT(-1)
i^2 = -1
i^3 = -i
i^4 = +1
 
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I do not understand what you mean by "The product of two minus -1 and the square of that". Literally interpreted, "two minus -1" is 2- (-1)= 3 but surely that is not what you mean. Did you mean "the product of -1, twice"? Does "that" refer to i? Yes, i^2= -1. The product of "-1, twice" is (-1)^2= 1. What does that have to do with i^2= -1?

If there is something you are "not getting", perhaps it is the difference between the "square" and the "square root". The square of -2 is (-1)(-1)= 1. But the square root of -1 is i.

(There is a "technical" point here: while every number has a single square, every complex number has two square roots. The two square roots of -1 are i and -i.)
 
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Oh boy, sorry. I'm a second language speaker so speaking English messes my train of thoughts. :P
Let me repair the situation:
So, I have been taught that:''the product of two radicals is the same as the radical of the product, and vice versa.''-purplemath
But, now, dealing with the imaginary number:
We know that i=sqroot(-1).
So, i^2 should equal 1 since:
i^2=sqroot(-1)xsqroot(-1)=sqroot(-1x-1)=sqroot(1)=1

But, that makes no sense because it is said that i^2=-1

Is the property that I have been taught wrong? If so, when can I not use it?
 
The square root has an ambiguity in the complex numbers. You cannot use all the regular operations possible with positive real numbers.
 
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@alingly1: You may find this post in the FAQ section by micromass interesting:

https://www.physicsforums.com/showthread.php?t=637214

You will find a discussion of some of the "paradoxes" arising from mis-using the usual rules of arithmetic with complex numbers.
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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