Impact and the Coefficient of Restitution

AI Thread Summary
The coefficient of restitution applies specifically to the normal velocity component, as energy loss occurs during the compression and expansion of an object upon impact. To calculate the resulting velocity after a collision, one must resolve the initial velocity into components, focusing on the normal component for the coefficient of restitution. The speed in the perpendicular direction remains unchanged immediately after the collision, assuming no friction between the ball and the wall. Discussions highlight that oblique bouncing with friction introduces complexity, as it can cause the ball to rotate and experience rolling resistance. Overall, understanding these principles is crucial for accurately predicting the behavior of bouncing objects.
Vladimir_Kitanov
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Homework Statement
V1=50 ft/m
e = 0,75
Relevant Equations
e=(relative velocity after collision)/(relative velocity before collision)
Last post with picture, after this i will use Latex.

She say that correct answer is 41 ft/m.

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IMG_20220730_194136.jpg

Is this correct?
 
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I get answer b). ##41 \ ft/m##
 
The coefficient of restitution applies only to the normal velocity component.

PS effectively you just multiplied 50 by 0.75.
 
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PeroK said:
The coefficient of restitution applies only to the normal velocity component.
Why only to normal velocity?
And how to calculate x then?
 
Vladimir_Kitanov said:
Why only to normal velocity?
Because the energy lost is in the compression and subsequent expansion of the object, and the extent of the compression depends on the velocity component normal to the contact surface.
Vladimir_Kitanov said:
And how to calculate x then?
Resolve the initial velocity into components.
 
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Normal component is in x direction, and ball bounce of wall just in x direction.That is why we can use coefficient of restitution in that direction?
And speed in y is same because we need to calculate speed right after collision?
Is that correct?
 
I guess one has to assume that there is no friction between the ball and the wall so that the compression is only in the horizontal direction.
 
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malawi_glenn said:
I guess one has to assume that there is no friction between the ball and the wall so that the compression is only in the horizontal direction.
Yes, and that.
 
malawi_glenn said:
I guess one has to assume that there is no friction between the ball and the wall so that the compression is only in the horizontal direction.
Oblique bouncing with friction is quite complicated. Assuming no slipping, as the ball compresses, the frictional component of the reaction force exerts a torque about the ball's centre, causing it to start rotating. So now we have rolling resistance as a new part of the ball starts to compress and a corresponding part starts to decompress.
Superballs (https://en.wikipedia.org/wiki/Super_Ball), popular in the late '60s, could acquire so much spin that at the next bounce they would reverse direction, bouncing back and forth between two points on the floor.
 
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