Impact loading for a lowered object

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SUMMARY

The discussion focuses on calculating impact loads when a mass is lowered by a crane onto a beam at a constant speed. The classic impact equation is adapted using the conservation of energy principle, leading to the formula for vertical displacement: x = v√(m/k). The impact load is defined as F_i = v√(km), where m is the mass, v is the speed, and k is the vertical stiffness of the beam. This approach provides a simplified method to assess the forces involved during the lowering process.

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Bucko1
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hi,

Trying to look at the impact loads on an object when it is lowered by a crane. Assuming a constant crane lowering speed and a known stiffness of the item onto which the object is lowered. ie a mass being lowered onto a beam at a constant speed. I've looked at the classic impact equation for the dropping of objects onto beams , but not sure how to adjust them for lowering of a suspended mass. Any help will be much appreciated.

Cheers
 
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A lot depends upon the shape of the two surfaces where they will come in contact. What did you have in mind?
 
A very crude approximation would be the conservation of energy:
$$E_k = E_s$$
$$\frac{1}{2}mv^2 = \frac{1}{2}kx^2$$
$$x = v\sqrt{\frac{m}{k}}$$
Where:
  • ##m## is the mass of the object;
  • ##v## is the speed of the object;
  • ##k## is the vertical stiffness of the beam;
  • ##x## is the vertical displacement of the beam.
The impact load is then ##F_i = kx = kv\sqrt{\frac{m}{k}}= v\sqrt{km}##.
 

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