1. The problem statement, all variables and given/known data An offshore crane is lowering a load with a constant speed of 0.2 m/s. The crane tip has a maximum vertical and horizontal acceleration, as a result of a seastate, of 2.0 m/s2 (vertical) and 0.8 m/s2. The crane needs to lower a 200 ton object onto a stationary object. The stationary object is fixed to the seabed and sticks out of the water. No wave slamming forces are present. 2. Relevant equations Determine the maximum load at the crane tip. Determine the vertical and horizontal impact load upon lowering of the 200 ton object to the stationary object. 3. The attempt at a solution Fvertical = m × a m = 200000 kg a = 2 m/s2 Fvertical = 200000 × 2 = 400000 N = 40.775 ton Fhorizontal = m × a m = 200000 kg a = 0.5 m/s2 Fhorizontal = 200000 × 0.5 = 100000 = 10.194 ton Am I missing something in this?