Impact parameter dependence of classical scattering angle

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otg
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Homework Statement


The problem is to get the classical turning point as a function of the impact parameter b for the Lennard-Jones potential.

Homework Equations


The Lennard-Jones potential is given as [itex]V(r)=4\epsilon[(\frac{\sigma}{r})^{12}-(\frac{\sigma}{r})^6][\itex].<br /> The effective potential is [itex]V_{eff}(r)=V(r)+E\frac{b^2}{r^2}[\itex].<br /> Also, [itex]\frac{m}{2}\dot{r}+V_{eff}(r)=E[\itex].<br /> <br /> <h2>The Attempt at a Solution</h2><br /> Since the turning point occurs when [itex]\dot{r}=0[\itex], we have that [itex]4\epsilon[(\frac{\sigma}{r})^{12}-(\frac{\sigma}{r})^6]+E\frac{b^2}{r^2}=E[\itex]. Even though [itex]\sigma,\,\epsilon\,\text{and }\,E[\itex] are given, I find it quite hard if not impossible to solve the equation to get [itex]r(b)[\itex]. There has to be some other way even if this was the indicated strategy.<br /> <br /> The exercise says that the equation [itex]V_{eff}(r)=E[\itex] can be rewritten as a polynomial and solved with a computer program, but since it becomes (at least that's what I get) a twelve degree polynomial in [itex]r[\itex] it's not possible to get a decent answer.<br /> <br /> Grateful for any kind of help how to proceed. And also how to get the latex working in the posts...[/itex][/itex][/itex][/itex][/itex][/itex][/itex][/itex][/itex]
 
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otg said:

Homework Statement


The problem is to get the classical turning point as a function of the impact parameter b for the Lennard-Jones potential.

Homework Equations


The Lennard-Jones potential is given as [itex]V(r)=4\epsilon[(\frac{\sigma}{r})^{12}-(\frac{\sigma}{r})^6][/itex].
The effective potential is [itex]V_{eff}(r)=V(r)+E\frac{b^2}{r^2}[/itex].
Also, [itex]\frac{m}{2}\dot{r}+V_{eff}(r)=E[/itex].

The Attempt at a Solution


Since the turning point occurs when [itex]\dot{r}=0[/itex], we have that [itex]4\epsilon[(\frac{\sigma}{r})^{12}-(\frac{\sigma}{r})^6]+E\frac{b^2}{r^2}=E[/itex]. Even though [itex]\sigma,\,\epsilon\,\text{and }\,E[/itex] are given, I find it quite hard if not impossible to solve the equation to get [itex]r(b)[/itex]. There has to be some other way even if this was the indicated strategy.

The exercise says that the equation [itex]V_{eff}(r)=E[/itex] can be rewritten as a polynomial and solved with a computer program, but since it becomes (at least that's what I get) a twelve degree polynomial in [itex]r[/itex] it's not possible to get a decent answer.

Grateful for any kind of help how to proceed. And also how to get the latex working in the posts...
use / sign not \ after ending( i don't think there is a simple way)
 
andrien said:
use / sign not \ after ending( i don't think there is a simple way)

ha ha ok my fingers must've gone into LaTeX mode :)

To reply on my own post then, no there is no simple way, I think I interpreted the question "solve for r as function of b" as "find an expression" but the task was as simple as plot the roots to find the functional behavior. Thanx for pointing out the /-thing though (probably would have worked next time without me knowing what went wrong) :)