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Homework Statement
The problem is to get the classical turning point as a function of the impact parameter b for the Lennard-Jones potential.
Homework Equations
The Lennard-Jones potential is given as [itex]V(r)=4\epsilon[(\frac{\sigma}{r})^{12}-(\frac{\sigma}{r})^6][\itex].<br /> The effective potential is [itex]V_{eff}(r)=V(r)+E\frac{b^2}{r^2}[\itex].<br /> Also, [itex]\frac{m}{2}\dot{r}+V_{eff}(r)=E[\itex].<br /> <br /> <h2>The Attempt at a Solution</h2><br /> Since the turning point occurs when [itex]\dot{r}=0[\itex], we have that [itex]4\epsilon[(\frac{\sigma}{r})^{12}-(\frac{\sigma}{r})^6]+E\frac{b^2}{r^2}=E[\itex]. Even though [itex]\sigma,\,\epsilon\,\text{and }\,E[\itex] are given, I find it quite hard if not impossible to solve the equation to get [itex]r(b)[\itex]. There has to be some other way even if this was the indicated strategy.<br /> <br /> The exercise says that the equation [itex]V_{eff}(r)=E[\itex] can be rewritten as a polynomial and solved with a computer program, but since it becomes (at least that's what I get) a twelve degree polynomial in [itex]r[\itex] it's not possible to get a decent answer.<br /> <br /> Grateful for any kind of help how to proceed. And also how to get the latex working in the posts...[/itex][/itex][/itex][/itex][/itex][/itex][/itex][/itex][/itex]
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