Impedance across AC voltage source

  • Thread starter Simfish
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  • #1
Simfish
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Homework Statement



An impedance 1000(1 + i) Ω (and note it contains an imaginary
part) is connected across an AC voltage source of amplitude 10 V
and frequency 60 Hz. Whatʼs the power dissipated during one cycle
within the impedance?

Homework Equations



P = Re(V*I), where V* is complex conjugate of voltage
I=V/Z

The Attempt at a Solution



So it's alternating current, so I first take the RMS V:[tex]10/\sqrt{2}[/tex]. Then I = V/Z, so I get

[tex]V*I = V*V/Z = 100/2 \frac{1}{1000(1+i)} = \frac{1-i}{20*2}[/tex]. Then I take the real part of this, which is 1/40. Am I doing this right?

Thanks!
 

Answers and Replies

  • #2
ehild
Homework Helper
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1,912
Correct!

ehild
 

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