# Impedance across AC voltage source

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## Homework Statement

An impedance 1000(1 + i) Ω (and note it contains an imaginary
part) is connected across an AC voltage source of amplitude 10 V
and frequency 60 Hz. Whatʼs the power dissipated during one cycle
within the impedance?

## Homework Equations

P = Re(V*I), where V* is complex conjugate of voltage
I=V/Z

## The Attempt at a Solution

So it's alternating current, so I first take the RMS V:$$10/\sqrt{2}$$. Then I = V/Z, so I get

$$V*I = V*V/Z = 100/2 \frac{1}{1000(1+i)} = \frac{1-i}{20*2}$$. Then I take the real part of this, which is 1/40. Am I doing this right?

Thanks!

ehild
Homework Helper
Correct!

ehild