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Impedances in a 5 element circuit

  1. Jun 20, 2017 #1
    1. The problem statement, all variables and given/known data
    upload_2017-6-20_22-42-59.png
    upload_2017-6-20_22-43-14.png

    Just help me with 18 b.

    2. Relevant equations
    V1 = c1I1Z1. Same for V2,3,45. V = V1+V2+V3+V4+V5. V/I=Z=impedance.

    3. The attempt at a solution
    Maybe because of symmetry Z1=Z2 & Z3=Z4. Perhaps Z5 takes out one of the branches??? Can I get a hint?
     
  2. jcsd
  3. Jun 25, 2017 #2

    phinds

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    Trying to read your image gives me eyestrain, but if Z1=Z2 & Z3=Z4 then what is I5 ?
     
  4. Jun 25, 2017 #3
    https://1drv.ms/b/s!ApJAu5EMYb4JgpYy68UWlGVzp0PVLQ -- Here's the link if it helps you see better. problem 18b.



    I would not assume anything is equal to another unless the problem explicitly says that
     
  5. Jun 25, 2017 #4

    phinds

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    I am following up on what YOU said not what the problem statement said
     
  6. Jun 25, 2017 #5
    Oh!!! I was just guessing. I forgot to tell you, I basically solve this using loop current method & current equalities. Here's a link to my teacher's answer if it'll help.

    https://1drv.ms/b/s!ApJAu5EMYb4JgpYqh2SQVlgB1Tevvw
     
  7. Jun 25, 2017 #6
    One more thing: I still don't know how they jumped from the 2nd to last line to the last line in this problem (in the answer I mean).
     
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