Implicit differentiation find dy/dx and d2y/dx2

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SUMMARY

The discussion focuses on finding the first and second derivatives of the implicit function defined by the equation 2xy = 3x - y². The first derivative, dy/dx, is confirmed to be (3 - 2y) / (2x + 2y). The second derivative, d²y/dx², is derived using the quotient rule and implicit differentiation, resulting in the expression (-12x + 2x²y + 9 + 4yx - 14y - 4y²) / ((x + y)(2x + 2y)²). Participants validate the correctness of the derivatives and discuss simplification techniques.

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mattmannmf
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2xy=3x-y^2

find dy/dx and d2y/dx2

I just want to make sure my answer is right and simplified

I got dy/dx= (3-2y)/ (2x+2y)

Now d2y/dx2 took some time but this is what i got:

(-12x+2x2y+9+4yx-14y-4y^2) / ((x+y)(2x+2y)^2)
 
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Your dy/dx is correct. I didn't work out the second derivative, but as long as you took the derivative of dy/dx using the quotient rule and implicit differentiation, replacing dy/dx in that expression with what you found, and then simplifying correctly, then you did it right.
 
yeah, i did that must i just wasn't to sure with my algebra (thats usually the step i would mess up). thanks though!
 
I don't know if you can reduce this to a more simpler form but this is simplest i got: y"=(3-2y)(3+8x+6y)/8(x+y)^3
 
was this from the equation i have up there or did u do this from the beginning of the problem?
 
the answer is yes and yes.
 

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