How do I find f'(1) using implicit differentiation?

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To find f'(1) using implicit differentiation for the equation x^3 f(x) + (f(x))^3 + f(x^3) = 3 with f(1) = 2, differentiate both sides with respect to x. The derivative results in 3x^2 f(x) + x^3 f'(x) + 3(f(x))^2 f'(x) + f'(x^3)(3x^2) = 0. After substituting x = 1 and f(1) = 2 into the differentiated equation, solve for f'(1). Additionally, a formatting error in the original post led to confusion about unrelated derivative questions, emphasizing the importance of maintaining topic focus in discussions. The thread highlights the process of using implicit differentiation to find specific derivatives effectively.
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"implicit differentiation"

if [x][3] * f(x) + [(f(x))][3] + f([x][3]) = 3 and f(1)= 2 find f'(1)

NEED HELP REVIEW QUESTION FROM EXAM REVIEW
DONT KNOW WHAT TO DO
 
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x^3 * f(x) + (f(x))^3 + f(x^3) = 3
and f(1) = 2 find f'(1)

formating error in original post
 


Use "implicit differentiation": (x^3 f(x)+ (f(x))^3+ f(x^3))'= 3x^2f(x)+ x^3 f'(x)+ 3f(x)^2 f'(x)+ f'(x^3)(3x^2)= 0. Set x= 1 and solve for f'(1).
 


i have a derivative problem that reads 4/ ^5sqrt(x^5). I am not sure how to work the problem out.
 


1. Please don't hijack other peoples threads for new questions- start your own thread.
2. I have no idea what "4/ ^5" is supposed to mean.
3. sqrt(x^5)= x5/4.
 

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