Impulse and Momentum, 2 dimension

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 replies · 2K views
buttretler
Messages
8
Reaction score
0
Been stuck on this question for days and any help would be greatly appreciated

A baseball going horizontally at 32.0 m/s [E] with a mass of 0.152 kg is hit by a bat for 0.002 seconds. the velocity after the ball after contact is 52.0 m/s [W 20 N]

Find the impulse experienced by the ball. (I'm guessing total impulse, first vector and the other)

pretty much what i have to work with is F net Δt = m(v2-v1)


Tutors keep telling me I'm wrong without pointing me in the right direction just adding more confusion. here is what i did. ...

V1 being its initial vector

v1x = 32cos0 = 32
v1y = 32sin0 = 0

V2 being after collision

v2x = -52cos20 = -48.864
v2y = 52sin20 = 17.785

now applying Fnet Δt = m(v2-v1) for x and y components.

fnetx Δt = m(-80.864)
fnetx(0.002)=0.152(-80.864)
fnetx = -6145.664

then same stuff for y

fnety =1351.664

after that i use both values to plug into a triangle then Pythagorean to find unknown side which to me seems like it would be the impulse of the ball. which i got 6292.5 kg m/s.

I need help with this, I just can't seem to rack my brain around what is wrong. Things I'm pretty sure I need to use is the fnet Δt=m(v2-v1) and some kind of triangle.

Thanks a lot in advance guys.
 
on Phys.org
heres what i did
 

Attachments

  • baseball.jpg
    baseball.jpg
    27.4 KB · Views: 564